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AnnyKZ [126]
3 years ago
10

If 1.0kg of juice of a specific heat capacity 3.0kj/kg degrees c at a temperature of 10 degrees celsius is poured into a 1.0kg g

lass bowl that is 15 degrees celsius. determine the final temperature of the juice.
Physics
1 answer:
AlladinOne [14]3 years ago
3 0

We have heat lost by water is equal to heat gained by Juice.

Heat exchanged is calculated using the formula,

\Delta H=ms \Delta T

Let T_f be the final temperature then,

(1)(3)(T_f-10)=(1)(4.187)(15-T_f)\\  3T_f-30=62.805-4.187T_f\\  7.187T_f=92.805\\  T_f=12.913 K

The final temperature of the juice is 12.913 K.

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Sunlight shines through a salt shaker. Should you expect more, less, or the same amount of scattering from blue light compared t
pshichka [43]

Blue light will scatter more compared to red light.

Blue light has a short wavelength; red light a longer wavelength. The sky looks blue because blue light is scattered far more than red light, owing to the shorter wavelength of blue light.

<h3>What is scattering of light?</h3>

Scattering of light is the phenomenon in which light rays deviate from their original path upon striking an obstacle like dust, gas molecules or water vapors. Scattering of light gives rise to many spectacular phenomena such as Tyndall effect and the red hues that can be seen at sunrise and sunset.

<h3>What is the scattering of light with example?</h3>

Some example of scattering of light that we come across in day-to-day life are: Blue colour of the sky: Out of the seven components present in sunlight, blue colour is scattered the most by the particles present in the atmosphere and hence, the sky appears blue.

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4 0
2 years ago
A strong lightning bolt transfers about 25 C to earth. how many electrons are transferred?
Aneli [31]

Answer:

n = 1.563x {10}^{20}

8 0
2 years ago
If an object emits or reflects light, A. it has a smooth surface. B. it can be seen by the eye. C. it must be the color white. D
kirill [66]

Answer:

It can be seen by the eye

Explanation:

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5 0
3 years ago
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A voltmeter and an ammeter are used to respectively monitor the voltage across and the current through a resistor connected to a
dsp73

Answer:

(a) 95 volt

(b)  134.33 volt

(c) 10.746 volt

(d) Average delivered power is 722 watt  

Explanation:

We have given value of resistance R = 12.5 ohm

Current in the ammeter i = 7.60 A

(a) Rms voltage in the resistor V=iR=7.6\times 12.5=95volt

(b) We know that rms voltage is given by v_r=\frac{v_m}{\sqrt{2}}

v_m=\sqrt{2}v_r=1.414\times 95=134.33volt

So peak voltage will be equal to 134.33 volt

(c) Maximum current is equal to i_m=\sqrt{2}i_r=1.414\times 7.6=10.746A

(d) Average power delivered in the resistor is equal to

P = VI

So P=95\times 7.6=722watt

7 0
3 years ago
four objects are situated along the y axis as follows: a 2.00kg object is at +3.00m. a 3.00kg object is at +2.50m, a 2.50kg obje
Mashutka [201]

The centre of mass of the objects is (0,1)m .

What do you mean by Centre of mass?

The centre of mass is a position defined relative to an object or system of objects .

We have given

m1=2kg , y1= 3

m2= 3kg ,y2=2.5m

m3=2.5kg ,y3= 0m

m4=4kg , y4= -0.5m

Ycm=mixi/mi

→2×3+3×2.5+2.5×0+4×0.5/4.5

→1m

Centre of mass of these object is at (0,1)m .

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4 0
2 years ago
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