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AnnyKZ [126]
3 years ago
10

If 1.0kg of juice of a specific heat capacity 3.0kj/kg degrees c at a temperature of 10 degrees celsius is poured into a 1.0kg g

lass bowl that is 15 degrees celsius. determine the final temperature of the juice.
Physics
1 answer:
AlladinOne [14]3 years ago
3 0

We have heat lost by water is equal to heat gained by Juice.

Heat exchanged is calculated using the formula,

\Delta H=ms \Delta T

Let T_f be the final temperature then,

(1)(3)(T_f-10)=(1)(4.187)(15-T_f)\\  3T_f-30=62.805-4.187T_f\\  7.187T_f=92.805\\  T_f=12.913 K

The final temperature of the juice is 12.913 K.

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During an episode of turbulence in an airplane you feel 210 n heavier than usual.if your mass is 72 kg, what are the magnitude a
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It is epistemically possible that a completed physics might include which of the following propositions? O Souls and other spiri
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option D.

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What must happen to the temperature of a material for thermal expansion to occur.
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3 years ago
Two identical small charged spheres hang in equilibrium with equal masses (0.02kg). The length of the strings is equal (0.18m) a
Yuliya22 [10]

Answer:

The value is q = 3.4 *10^{-6} \ C

Explanation:

From the question we are told that

    The mass of each sphere is m_1 = m_2  = m  =  0.020 \ kg

     The length of the string is  l = 0.18 \  m

     The angle of with the vertical is \theta  =  7^o

      The acceleration due to gravity is g = 9.8 \ m/s^2

Generally the force acting between the forces is mathematically represented as

       F  =  T cos \theta =  \frac{k*  q^2}{ r^2}

=>     T cos \theta =  \frac{k*  q^2}{ r^2}

Generally from Pythagoras theorem the radius of the circular curve created by the force is

         r = 2 L sin (\theta )

=>      r = 2* 0.180 sin (7)

=>      r = 0.043 \ m  

=>     q = tan \theta * \frac{m * g * r^2 }{k}

=>      q = tan(7)* \frac{ 0.02 * 9.8 * 0.043^2 }{9*10^{9}}

=>      q = 3.4 *10^{-6} \ C

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