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AnnyKZ [126]
2 years ago
10

If 1.0kg of juice of a specific heat capacity 3.0kj/kg degrees c at a temperature of 10 degrees celsius is poured into a 1.0kg g

lass bowl that is 15 degrees celsius. determine the final temperature of the juice.
Physics
1 answer:
AlladinOne [14]2 years ago
3 0

We have heat lost by water is equal to heat gained by Juice.

Heat exchanged is calculated using the formula,

\Delta H=ms \Delta T

Let T_f be the final temperature then,

(1)(3)(T_f-10)=(1)(4.187)(15-T_f)\\  3T_f-30=62.805-4.187T_f\\  7.187T_f=92.805\\  T_f=12.913 K

The final temperature of the juice is 12.913 K.

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The current through a 10 ohm resistor connected to a 120 volt power supply is
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Answer:I=12 A

Explanation:

Given

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According to ohm's law current through a conductor is directly proportional to the voltage applied.

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2 years ago
When the displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position, what fraction of the
KonstantinChe [14]

Answer:

The ratio is  KE : TM  =  0.75

Explanation:

from the question we are told that

  The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position

Generally the total mechanical  energy of the mass is mathematically represented as

        TM  =  \frac{1}{2}  *  k  *  A^2

Here  k is the spring constant  ,  A is the total displacement of the  the mass  from maximum  compression to maximum extension of the spring

Generally this total mechanical energy is mathematically represented as

        TM  =  KE  + PE

=>     KE = TM  - PE

Here the potential  energy of the mass is mathematically represented as

     PE   = \frac{1}{ 2}  *  k *  [ x ]^2

Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is  

      x = \frac{A}{2}

So

     PE   = \frac{1}{ 2}  *  k *  [ \frac{A}{2}  ]^2

So

      KE =  \frac{1}{2}  *  k  *  A^2 - \frac{1}{2}  *  k  *  [\frac{A}{2} ]^2

=>    KE =  \frac{1}{2}  *  k  *  A^2 - \frac{1}{8}  *  k  *  A ^2

=>    KE =  0.375  *  k  *  A^2

So the ratio of  KE :  TM is  mathematically represented as

       \frac{KE}{TM} =  \frac{0.375  k A^2 }{0.5 k A^2}

=>    \frac{KE}{TM} = 0.75

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