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AnnyKZ [126]
3 years ago
10

If 1.0kg of juice of a specific heat capacity 3.0kj/kg degrees c at a temperature of 10 degrees celsius is poured into a 1.0kg g

lass bowl that is 15 degrees celsius. determine the final temperature of the juice.
Physics
1 answer:
AlladinOne [14]3 years ago
3 0

We have heat lost by water is equal to heat gained by Juice.

Heat exchanged is calculated using the formula,

\Delta H=ms \Delta T

Let T_f be the final temperature then,

(1)(3)(T_f-10)=(1)(4.187)(15-T_f)\\  3T_f-30=62.805-4.187T_f\\  7.187T_f=92.805\\  T_f=12.913 K

The final temperature of the juice is 12.913 K.

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grigory [225]

Yes, this equation is balanced.

You can check it using the law of conservation of mass, i.e., the total mass of the products formed must be equal to the total mass of the reactants.

7 0
2 years ago
A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav
gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2        (1)

m: mass of the person = 62kg

k: spring constant = ?

v: velocity of the person just when he touches the fire net = ?

x: elongation of the fire net = 1.4 m

Before the calculation of the spring constant, you calculate the final velocity of the person by using the following formula:

v^2=v_o^2+2gy

vo: initial velocity = 0 m/s

g: gravitational acceleration = 9.8 m/s^2

y: height from the person jumps = 20.0m

v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(20.0m)}=14\frac{m}{s}

With this value you can find the spring constant k from the equation (1):

mv^2=kx^2\\\\k=\frac{mv^2}{x^2}=\frac{(62kg)(14m/s)^2}{(1.4m)^2}=6200\frac{N}{m}

When the person is lying on the fire net the weight of the person is equal to the elastic force of the fire net:

W=F_e\\\\mg=kx

you solve the last expression for x:

x=\frac{mg}{k}=\frac{(62kg)(9.8m/s^2)}{6200N/m}=0.098m

When the person is lying on the fire net the elongation of the fire net is 0.098m

b) To find how much would the net stretch, If the person jumps from 38 m, you first calculate the final velocity of the person again:

v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(38m)}=27.29\frac{m}{s}

Next, you calculate x from the equation (1):

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(62kg)(27.29m/s)^2}{6200N/m}}\\\\x=2.72m

The net fire is stretched 2.72 m

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KATRIN_1 [288]
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Ugo [173]
Yes, C is correct. It self explains itself as we know light travels through a vacuum ( doesn't need a medium) and light is a type of electromagnetic wave.
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3 years ago
How many neutrons are needed to initiate the fission reaction shown?
nalin [4]

Answer: One neutron

Explanation:

one neutron 1/0n

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The sum of the mass numbers on the left should equal 236. 235 + 1 = 236

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