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g100num [7]
3 years ago
14

Light is admitted by electrons when they drop from one energy level to a lower level which transition results in the admission o

f light with the greatest energy
Level 2 to level 4
Level 3 to level 2
Level 4 to level 2
Chemistry
1 answer:
koban [17]3 years ago
3 0

The correct wording for the question is:

Light is emitted by electrons when they drop from one energy level to a lower leve. Which transition results in the emission of light with the greatest energy:

  • Level 2 to level 4
  • Level 3 to level 2
  • Level 4 to level 2

Answer:

  • Third option: level 4 to level 2.

Explanation:

The electron transition in an atom from an upper level of energy to a lower level of energy, i.e. the jump of an electron to a lower energy level, implies the emission of light energy and the release of energy of the electron, i.e. the electron changes its energy.

The larger the gap between the states that the electron jumps, the shorter the wavelength of the photon emitted, the higher its frequency and the energy emiited during such transition of the electron (remember energy is directly proportional to the frequency of the wave, and both are inversely related to the wavelength).

From the options given the larger jump is from level 4 to level 2, so that is the transition that results in the emission of light with the greatest energy, which is the last option.

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What are the smallest sub atomic structure
Anton [14]

Answer:

Electrons

Explanation:

In an atom there would be three subatomic particles: Neutrons, electrons, protons. The smallest and lightest in terms of mass is electrons. This is because the nucleus is comprised of the protons and the neutrons, these have a greater mass than electrons as electrons has very little mass that can considered to be 0.

7 0
3 years ago
Sodium hydroxide reacts with aluminum and water to produce hydrogen gas: 2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H
lianna [129]

Answer:

The mass of hydrogen gas formed is 0.205 grams

Explanation:

<u>Step 1:</u> Data given

Mass of 1.83 grams of Al

Mass of NaOH = 4.30 grams

Molar mass of Al = 26.98 g/mol

Molar mass of NaOH = 40 g/mol

<u>Step 2:</u> The balanced equation:

2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2(g)

<u>Step 3:</u> Calculate moles of Al

Moles Al = mass Al / Molar mass Al

Moles Al = 1.83 grams / 26.98 g/mol

Moles Al = 0.0678 moles

<u>Step 4:</u> Calculate moles of NaOH

Moles NaOH = 4.30 grams / 40 g/mol

Moles NaOH = 0.1075 moles

<u>Step 5</u>: Calculate limiting reactant

For 2 moles of Al, we need 2 moles of NaOH

Aluminium is the limiting reactant. It will completely be consumed ( 0.0678 moles)

NaOH is in excess. There will react 0.0678 moles

There will remain 0.1075 - 0.0678 = 0.0397 moles

<u>Step 6</u>: Calculate moles of hydrogen

For 2 moles of Al, we need 2 moles of NaOH, to produce 3 moles of hydrogen

For 0.0678 moles of Al, there is produced 0.0678 *3/2 = 0.1017 moles of H2

<u>Step 7</u>: Calculate mass of H2

Mass of H2 = Moles H2 * Molar mass of H2

Mass of H2 = 0.1017 moles * 2.02 g/mol

Mass of H2 = 0.205 grams

The mass of hydrogen gas formed is 0.205 grams

6 0
3 years ago
What solid element is black, is an electrical conductor, is brittle and is found in group 4 of the periodic table?​
elixir [45]

Answer: silicon Si, Germanium GE

Explanation:

4 0
3 years ago
Use the limiting reagent to determine how many grams of Cu(OH)2 should precipitate out in the reaction - CuSo4(aq) + 2NaOH(aq) -
Elis [28]
I think there is a lack of information in the given problem above such as the grams of copper sulfate and sodium hydroxide that was used in the experiment. Kindly resubmit the question with the complete details so that we can help you. Thank you.

7 0
3 years ago
Read 2 more answers
Express the concentration of a 0.0390 M aqueous solution of fluoride, F − , in mass percentage and in parts per million (ppm). A
Vadim26 [7]

Answer:

Mass percentage → 0.074 %

[F⁻] = 741 ppm

Explanation:

Aqueous solution of flouride → [F⁻] = 0.0390 M

It means that in 1L of solution, we have 0.0390 moles of F⁻

We need the mass of solution and the mass of 0.0390 moles of F⁻

Mass of solution can be determined by density:

1g/mL = Mass of solution / 1000 mL

Note: 1L = 1000mL

Mass of solution: 1000 g

Moles of F⁻ → 0.0390 moles . 19g /1 mol = 0.741 g

Mass percentage → (Mass of solute / Mass of solution) . 100

(0.741 g / 1000 g) . 100 = 0.074 %

Ppm = mass of solute . 10⁶ / mass of solution (mg/kg)

0.741 g . 1000 mg/1g = 741 mg

1000 g . 1 kg/1000 g = 1kg

741 mg/1kg = 741 ppm

5 0
3 years ago
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