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QveST [7]
3 years ago
7

H2(g) + O2(9) - H2O(1)

Chemistry
1 answer:
dlinn [17]3 years ago
6 0

Answer:

2H2(g) + O2(g) - 2H2O(l)

balanced reaction

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How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous sol
mojhsa [17]

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

2Al + 3Cu{(NO_3)}_2  \rightarrow 2Al{(NO_3)}_3 +3 Cu

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

Al \rightarrow Al^{3+} + 3e^-

And copper goes from +2 to 0

Cu^{2+} + 2e^-\rightarrow Cu

On balancing the number of electrons we get:

For 1 mole of Al 6e^- is required.

Therefore for 2 moles of Al,

Total (2\times6)F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

brainly.com/question/27985929

#SPJ4

4 0
1 year ago
Does this equation obey the law of conservation of mass: 2Z + 2HCI ➡️ ZnCI2 + H2​
MAXImum [283]

Answer:

2Zn + 2HCI ➡️ ZnCI2 + H2​

LHS of equation

Z = 2

H = 2

Cl = 2

RHS of equation

Zn = 1

Cl =2

H =2

as Zn is not equal in number of atoms on both sides of the equation, the equation does not obey the law of conservation of mass

Explanation:

the law of conservation mass states that the mass of an isolated system cannot be created nor destroyed by any chemical reaction or physical transformation. thus, there must be an equal number of atoms of an element present on both sides of the equation.

5 0
3 years ago
According to our textbook, write the formula for the anhydrous compound that was part of the mixture called natron that was used
bearhunter [10]

Answer:

The formula for the anhydrous compound that was part of the mixture called natron that was used by the Egyptians is Na2(CO3)10(H2O).

They use this compound for medicine, cookery, agriculture, in glass-making and to dehydrate egyptian mummies.

Compound of sodium carbonate and sodium bicarbonate was the name of the resulting hydrate that formed.

8 0
3 years ago
A 508-g sample of sodium bicarbonate (NaHCO3) contains how many moles of sodium bicarbonate (NaHCO3)?
Blizzard [7]

molar mass = (22.99) + (1.01) + (12.01) + 3(16.00)

molar mass = 84.01 g/mol

//

(508g)(1 mol/84.01 g) = 6.0

There are 6.0 moles of sodium bicarbonate

3 0
3 years ago
Compounds can not be separated by Response area means. Separating a compound requires a Response areareaction.
Aleks04 [339]

Answer:

use vinager

Explanation:

I did this heh :/

7 0
3 years ago
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