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Vika [28.1K]
3 years ago
14

If the radius of an atom is 60 pm and the radius of the Earth is 6000 km, by how many orders of

Physics
1 answer:
kherson [118]3 years ago
6 0

Answer:

1 x 10¹⁷

               

Explanation:

Given data:

        Radius of the earth  = 6000km

        Radius of an atom  = 60pm

Now, how many orders is the radius of the earth larger than an atom

Solution:

To solve this problem, let us express both quantity as the same unit;

         1000m  = 1km

    6000km  = 6000 x 10³m   =  6 x 10⁶m

    60pm;

            1 x 10⁻¹²m  = 1pm

    60pm  = 60 x  1 x 10⁻¹²m  = 6 x 10⁻¹¹m

Now;

The order:   \frac{6 x 10^{6} }{6 x 10^{-11} }   = 1 x 10¹⁷

               

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A parallel-plate capacitor in air has a plate separation of 1.31 cm and a plate area of 25.0 cm2. The plates are charged to a po
morpeh [17]

Answer:

a) before immersion

C = εA/d = (8.85e-12)(25e-4)/(1.31e-2) = 1.68e-12 F

q = CV = (1.68e-12)(255) = 4.28e-10 C

b) after immersion

q = 4.28e-10 C

Because the capacitor was disconnected before it was immersed, the charge remains the same.

c)*at 20° C

C = κεA/d = (80.4*)(8.85e-12)(25e-4)/(1.31e-2) = 5.62e-10 F

V = q/C = 4.28e-10 C/5.62e-10 C = 0.76 V

e)

U(i) = (1/2)CV^2 = (1/2)(1.68e-12)(255)^2 = 5.46e-8 J

U(f) = (1/2)(5.62e-10)(0.76)^2 = 1.62e-10 J

ΔU = 1.62e-10 J - 5.46e-8 J = -3.84e-8 J

8 0
3 years ago
Imagine you had a bar of gold and decided to cut in half. You repeated this process until eventually you could no longer cut the
nydimaria [60]

This would prove that gold is an <em>element</em>.  No matter how far down you
examine it, you never find any particles of anything except gold.

An example of a different case is salt. 
-- Imagine you had a block of salt and decided to cut it in half.
-- If you repeated this process, then eventually, at some point, you'd have
a tiny particle of salt in front of you, just like before.  BUT ...
-- Just as you were getting ready to cut this one in half, you'd notice that this
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and if you cut it in half, you would not have ANY salt.   <span />

This would prove that salt is a <em><u>compound</u></em>, made of atoms of two or more elements.

3 0
4 years ago
Read 2 more answers
We are given the description of an enclosure that has fencing on 3 sides and can use 3,056 yards of fencing. We are to find the
shusha [124]

Answer:

The sum of the lengths of the sides is 2292 yards and the sum of the lengths of the triangle is 3056 yards

Explanation:

Since y represents the length of fence that is opposite (parallel) to the river and x represent the length of fence perpendicular to the river.

Therefore since we can use 3,056 yards of fencing

Side perpendicular to the river = x and,

Side opposite to the river = y = 3056 - 2x

The area of the rectangle formed (A) = Perpendicular side × Parallel side

∴ A = x(3056 - 2x) = 3056x - 2x²

A = 3056x - 2x²

To maximize the area, A' (dA/dx) = 0

∴ A' = 3056 - 4x = 0

3056 - 4x = 0

4x = 3056

x = 764 yards

y =  3056 - 2x = 3056 - 2(764) = 1528 yards.

Side perpendicular to the river = 764 yards and,

Side opposite to the river = 1528 yards

The sum of the lengths of the sides = 764 + 1528 = 2292 yard and the sum of the lengths of the triangle = 764 + 764 + 1528 = 3056 yards

5 0
3 years ago
Use Newton's laws of motion to answer!
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Because the gravity near the earths crust/surface is greater than once in orbit it doesnt need any fuel because the earths gravatitional pul is keeping it in orbit just like it keeps the moon it orbit around it and the sun keeps the planets in its orbit
Hope This Helps!
7 0
3 years ago
Calculate the volume of this regular solid.
fenix001 [56]

Answer:

2122.64 cm^3

Explanation:

Some data in the problem are missing.

Missing values:

Radius of the cylinder: 13 cm

Height of the cylinder: 4 cm

The volume of a cylinder is given by

V=\pi r^2 h

where

r is the radius of the base of the cylinder

h is the height of the cylinder

In this problem, we have:

r = 13 cm (radius)

h = 4 cm (height)

Therefore, the volume of the cylinder is:

V=\pi (13)^2(4)=2122.64 cm^3

6 0
3 years ago
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