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Vika [28.1K]
2 years ago
14

If the radius of an atom is 60 pm and the radius of the Earth is 6000 km, by how many orders of

Physics
1 answer:
kherson [118]2 years ago
6 0

Answer:

1 x 10¹⁷

               

Explanation:

Given data:

        Radius of the earth  = 6000km

        Radius of an atom  = 60pm

Now, how many orders is the radius of the earth larger than an atom

Solution:

To solve this problem, let us express both quantity as the same unit;

         1000m  = 1km

    6000km  = 6000 x 10³m   =  6 x 10⁶m

    60pm;

            1 x 10⁻¹²m  = 1pm

    60pm  = 60 x  1 x 10⁻¹²m  = 6 x 10⁻¹¹m

Now;

The order:   \frac{6 x 10^{6} }{6 x 10^{-11} }   = 1 x 10¹⁷

               

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Anarel [89]

Answer:

R = 24.3 m

Explanation:

As we know that the orbital speed is given as

v = \sqrt{\frac{GM}{R + h}}

here we know that

v = 5500 m/s

R = 4.48 \times 10^6 m

h = 630 km

now we have

5500 = \sqrt{\frac{(6.6 \times 10^{-11})M}{4.48 \times 10^6 + 6.30\times 10^5}}

M = 2.34 \times 10^24 kg

now acceleration due to gravity of planet is given as

a = \frac{GM}{R^2}

a = \frac{(6.6 \times 10^{-11})(2.34 \times 10^{24})}{(4.48\times 10^6)^2}

a = 7.7 m/s^2

now range of the projectile on the surface of planet is given as

R = \frac{v^2 sin2\theta}{g}

R = \frac{14.6^2 sin(2\times 30.8)}{7.7}

R = 24.3 m

3 0
3 years ago
What is the density of an object with a mass of 60g and a volume of 2cm3?
zaharov [31]

m= 60g = 60/1000 Kg = 0.06 Kg v = 2cm3 = 2 * (0.01^3) m3 = 2 *10^-6 m3 Density= m/v = 6 * 10^-2 / 2 *10^-6  =  3 *10^4 Kg/m3

8 0
3 years ago
A wave travels through a medium because
Amanda [17]

in case you dont want to read the answer is B

5 0
3 years ago
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An ambulance is traveling east at 61.9 m/s. Behind it there is a car traveling along the same direction at 28.5 m/s. The ambulan
inessss [21]

Answer: 0.4 m

Explanation:

Given

Speed of ambulance, vs = 61.9 m/s

Speed of car = 28.5 m/s

Frequency of ambulance siren, f = 694 Hz

Velocity of sound in air, v = 343 m/s

With speed of ambulance being (61.9 m/s) -> We solve using

fd = f(v + vr) / (v - vs), where vr = 0

fd = 694 * (343 + 0) / (343 - 61.9)

fd = 694 * (343 / 281.1)

fd = 694 * 1.22

fd = 847 Hz

Recall,

λ = v/f

λ = 343/847

λ = 0.4 m

Therefore, the wavelength of the sound of the ambulance’s siren if you are standing at the position of the car is 0.4 m

7 0
3 years ago
Photon Lighting Company determines that the supply and demand functions for its most popular lamp are as follows: S(p) = 400 - 4
torisob [31]

Answer: The correct answer is (C).

Explanation:

Supply function:

S(p)=400-4p+0.00002p^4

Demand function:

D(p)=2800-0.0012p^3

S(p)=D(p), price for which supply is equal to demand:

S(p)=D(p)=400-4p+0.00002p^4=2800-0.0012p^3

After solving this above equation graphically, we will get the values of p.

1) p =96.236

2) p=( -118.258)

We will reject the negative value of p.

So, the value of p that price for which the supply equals the demand is $ 96.236 \approx $96.24. Hence, the correct answer is option (C).

6 0
3 years ago
Read 2 more answers
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