Answer:
F = k q1 q2 / r^2
r^2 = k q1 q2 / F = 9E9 * 4E-5 * 10.8E-5 / 4
r^2 = 9 * 4 * 10.8 / 4 * E-1 = 9.72 m^2
r = 3.12 m
centripetal acceleration always points towards the center of the circular path and velocity of object in circular motion always points towards the tangent on the the circle in this way centripetal acceleration and velocity are perpendicular to each other and the dot product of perpendicular vectors is always zero,
therefore v•a=vacosα...........(1)
here α is angle between centripetal acceleration and velocity which is 90
therfore,
From equation (1)
v.a= vacos90
v.a=vax0..............(because cos90=0)
v.a=0 m^2
centripetal acceleration vector points towards center it means it point towards inwards direction, so it lies along the radius vector,and radius vector points towards outward direction of the circle in this way centripetal acceleration and radius vector are in exact opposite direction so angle between them is 180 degree,
therefore r x a = rasin180
rxa=rax0 (because sin180=0)
rxa=0m^2/s^2 .
Answer:
Explanation:
The energy for an isothermal expansion can be computed as:
--- (1)
However, we are being told that the volume of the gas is twice itself when undergoing adiabatic expansion. This implies that:
Equation (1) can be written as:
Also, in a Carnot engine, the efficiency can be computed as:
In addition to that, for any heat engine, the efficiency e =
relating the above two equations together, we have:
Making the work done (W) the subject:
From equation (1):
If we consider the adiabatic expansion as well:
= constant
i.e.
From ideal gas PV = nRT
we can have:
From the question, let us recall aw we are being informed that:
If the volumes changes by a factor = 5.7
Then, it implies that:
∴
In an ideal monoatomic gas 
As such:
Replacing the value of into equation
From in the question:
W = 930 J and the moles = 1.90
using 8.314 as constant
Then:
From
