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serg [7]
3 years ago
9

A wire is stretched just to its breaking point by a force F . A longer wire made of the same material has the same diameter. The

force that will stretch the longer wire to its breaking point is much smaller than F?
Physics
2 answers:
ICE Princess25 [194]3 years ago
8 0

Answer: No

Explanation:

The force F required is equal to the Force exerted in stretching the first material since conditions are the same

Viefleur [7K]3 years ago
6 0

Answer:

No.

Explanation:

Both wires are made up of the same material which means they will have the same young modulus.

Y = F/A × L/ΔL

From the equation above, the force applied per cross sectional (same diameter) are is the same for both materials and is constant.

So

L1/ΔL1 = L2/ΔL2

Or L2/L1 = ΔL2/ΔL1

So the force needed to bring about a stretching the the breaking point is the same. The only difference is in by how much the longer wire would have to stretch before reaching its breaking point.

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laiz [17]

For velocity vs Time graphs, the displacement of the object from 2 seconds to 6 seconds is 30 m.

<h3>What is displacement?</h3>

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

In velocity time graphs, the displacement is the area under the curve of the graph on the x axis.

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A line starts at (0, 2) and ends at (6, 8) in v-t graph

Displacement is equal to the area of a triangle and a rectangle formed under the line.

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Area = 18 +12

Area = 30 m

Thus, the displacement is 30 m.

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2 years ago
When a customer in Japan was quoted a price of .39 cents a pound he thought he was being charged .39 a kilogram. He was shocked
Anon25 [30]

Answer: $85.80

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Vlad1618 [11]

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3 years ago
A description of both speed and direction
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13. A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V a
Lisa [10]

Answer:

The output power is 2 kW

Explanation:

It is given that,

Number of turns in primary coil, N_p=250

Number of turns in secondary coil, N_s=500

Voltage of primary coil, V_p=200\ V

Current drawn from secondary coil, I_s=5\ A

We need to find the power output. It is equal to the product of voltage and current. Firstly, we will find the voltage of secondary coil as :

\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}

\dfrac{250}{500}=\dfrac{200}{V_s}

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So, the power output is :

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