The speed of the plane through the air is 430 mph, and you described a day when the wind was blowing at 20 mph.
Answer:
b it is b part answer i think so
Answer:
block 2 or 4
because of the distribution of weight and force being applied to the object
Answer
given,
Pressure on the top wing = 265 m/s
speed of underneath wings = 234 m/s
mass of the airplane = 7.2 × 10³ kg
density of air = 1.29 kg/m³
using Bernoulli's equation
Applying newtons second law
2 Δ P x A - mg = 0
A = 3.53 m²
Answer:
The maximum kinetic energy of the photoelectrons ejected from the surface is 5.22×10^-20 J.
Explanation:
let h = 6.626×10^-34 J×s be the planck constant.
let f be the frequency of light.
let Ф = 2.20×1.60×10^-19 = 3.52×10^-19 J be the work function.
then, the relationship between the kinetic energy of photoelectrons K, the energy provided by the light E and the work function of the material is given by:
K = h×f - Ф
= (6.626×10^-34)×(6.10×10^14) - 3.52×10^-19
= 5.22×10^-20 J
Therefore, the maximum kinetic energy of the photoelectrons ejected from the surface is 5.22×10^-20 J.
