All categories

3 years ago

An object moving at a constant velocity will always have a what

Physics

2 answers:

NNADVOKAT [17]3 years ago

8 0

An object moving at a constant velocity will always have a zero acceleration.

telo118 [61]3 years ago

4 0

Answer:

zero acceleration

Explanation:

Acceleration is defined as the rate change of velocity with respect to time

This means that:

$acceleration = \frac{delta_v_e_l_o_c_i_t_y}{delta_t_i_m_e}$

Now, since the velocity is given as a constant, this means that the value of the velocity does not change which means that the change of velocity is zero.

Substitute in the formula:

$acceleration = \frac{0}{delta_t_i_m_e} = 0$

Therefore, for constant velocity, the acceleration is zero.

Hope this helps :)

You might be interested in

Which of the following is an example of the law of conservation of energy?

Mashutka [201]

Answer:

turning lights of when you aren't using them

7 0

3 years ago

Read 2 more answers

Where are the life forms of the biosphere located

bulgar [2K]

The life forms of the biosphere are located within Earth's surface.

7 0

3 years ago

The initial volume reading in a graduated cylinder is 30 mL. The mass of an irregular shape of an unknown metal piece is 55.3 g.

Vadim26 [7]

Answer:

7.9 $\frac{gr}{cm^3}$

Explanation:

When we put the metal piece in the liquid (which is in the graduated cylinder), how much it goes up is equal to the volume of the piece we inserted.

So now we know that the volume of that piece of unknown metal is 7mL (which is the same as 7 $cm^3$ ).

Density is $\frac{mass}{volume}$ .

So the density of that piece of metal is $\frac{55.3g}{7cm^3}$

Which leaves us with a final density of 7.9 $\frac{gr}{cm^3}$

6 0

3 years ago

For the material in the previous question that yields at 200 MPa, what is the maximum mass, in kg, that a cylindrical bar with d

Sedaia [141]

Answer:

The maximum mass the bar can support without yielding = 32408.26 kg

Explanation:

Yield stress of the material ( $\sigma$ ) = 200 M Pa

Diameter of the bar = 4.5 cm = 45 mm

We know that yield stress of the bar is given by the formula

Yield Stress = $\frac{Maximum load}{Area of the bar}$

⇒ $\sigma$ = $\frac{P_{max} }{A}$ ---------------- (1)

⇒ Area of the bar (A) = $\frac{\pi}{4}$ × $D^{2}$

⇒ A = $\frac{\pi}{4}$ × $45^{2}$

⇒ A = 1589.625 $mm^{2}$

Put all the values in equation (1) we get

⇒ $P_{max}$ = 200 × 1589.625

⇒ $P_{max}$ = 317925 N

In this bar the $P_{max}$ is equal to the weight of the bar.

⇒ $P_{max}$ = $M_{max}$ × g

Where $M_{max}$ is the maximum mass the bar can support.

⇒ $M_{max}$ = $\frac{P_{max} }{g}$

Put all the values in the above formula we get

⇒ $M_{max}$ = $\frac{317925}{9.81}$

⇒ $M_{max}$ = 32408.26 Kg

There fore the maximum mass the bar can support without yielding = 32408.26 kg

3 0

3 years ago

What is the basic equation that defines velocity?

mr Goodwill [35]

Change in position (triangleV) divided by change in time (triangleT)

7 0

2 years ago