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Molodets [167]
3 years ago
10

An object moving at a constant velocity will always have a what

Physics
2 answers:
NNADVOKAT [17]3 years ago
8 0
<span>An object moving at a constant velocity will always have a zero acceleration. </span>
telo118 [61]3 years ago
4 0

<em><u>Answer:</u></em>

zero acceleration

<em><u>Explanation:</u></em>

<u>Acceleration</u> is defined as the rate change of velocity with respect to time

<u>This means that:</u>

acceleration = \frac{delta_v_e_l_o_c_i_t_y}{delta_t_i_m_e}

Now, since the velocity is given as a constant, this means that the value of the velocity does not change which means that the change of velocity is zero.

<u>Substitute in the formula:</u>

acceleration = \frac{0}{delta_t_i_m_e} = 0

<u>Therefore,</u> for constant velocity, the acceleration is zero.

Hope this helps :)

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Georgia [21]

Answer:

The answer is below

Explanation:

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Solution:

Acceleration is the time rate of change of velocity. It is the ratio of the change in velocity to the change in time. The acceleration can be gotten from a velocity time graph by finding the slope of the graph.

The x coordinate represent the time and the y coordinate velocity.

5) Graph A passes through the point (0, 0) and (4, 24). Therefore the acceleration (slope) is:

Acceleration = \frac{24-0}{4-0}=6\ m/s^2

This is correct.

6) Graph B is a straight line of 12 m/s. It passes through (0, 12) and (4, 12). Hence:

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This is false.

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8 0
2 years ago
Metallic bonds are responsible for many properties of metals, such as conductivity. Why is this possible? (1 point)
qaws [65]

Answer:

The bonds can shift because valence electrons are held loosely and more freely

Explanation:

Please give brainliest if you can,have a good day<3 :)

4 0
2 years ago
Why is it important to select a coordinate system when studying motion?
kvv77 [185]

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5 0
3 years ago
Calculate the work done if a boy lifts a bag of cement 500N to the floor of a lorry 2.5m above the ground
eduard

Answer:

W = 1250 J = 1.25 KJ

Explanation:

The work done by the boy is due to the change in the position of the cement vertically. Hence, the work done in this case will be equal to the potential energy of the cement:

W = P.E\\W = mgh

where,

W = Work done = ?

mg = W = weight of cement = 500 N

h = height covered = 2.5 m

Therefore,

W = (500\ N)(2.5\ m)

<u>W = 1250 J = 1.25 KJ</u>

4 0
2 years ago
What is the name of the ratio of the voltage applied to a circuit and the current in a circuit
malfutka [58]
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4 0
3 years ago
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