Mass of CO₂ evolved : 0.108 g
<h3>Further explanation</h3>
Given
1.205g sample, 36% MgCO3 and 44% K2CO3
Required
mass of CO2
Solution
0.36 x 1.205 g=0.4338 g
mass C in MgCO₃(MW MgCO₃=84 g/mol, Ar C = 12/gmol)
= (12/84) x 0.4338
= 0.062 g
0.44 x 1.205 g = 0.5302 g
Mass C in K₂CO₃(MW=138 g/mol) :
= (12/138) x 0.5302
= 0.046 g
Total mass Of CO₂ :
= 0.062 + 0.046
= 0.108 g
Answer:
<h3>The answer is option A</h3>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
<h3>Force = mass × acceleration</h3>
From the question
mass = 2 kg
acceleration = 3 m/s²
We have
Force = 2 × 3
We have the final answer as
<h3>6.0 N</h3>
Hope this helps you
Answer:
6 second???
Explanation:
Im so sorry if thats wrong!!!!
Answer:
C₁₆H₃₂O₂ (s) + 22O₂(g) → 16CO₂(g) + 16H₂O(g)
Explanation:
In order to determine a combustion reaction we should know that:
Reactants are: X compound and O₂
Products are: CO₂ and H₂O
In this case, the X compound is the solid palmitic acid: C₁₆H₃₂O₂
The balanced equation will be:
C₁₆H₃₂O₂ (s) + 22O₂(g) → 16CO₂(g) + 16H₂O(g)
Answer:
Developing the problem
Explanation:
In order to have an experiment or to make the experiment's data useful, you must first find a problem to solve.
