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viva [34]
3 years ago
10

How many moles of nitrogen are present at STP if the volume is 846L

Chemistry
1 answer:
Artyom0805 [142]3 years ago
3 0
A mole of any gas occupied 22.4 L at STP. So, the number of moles of nitrogen gas at STP in 846 L would be 846/22.4 = 37.8 moles of nitrogen gas.

Alternatively, you can go the long route and use the ideal gas law to solve for the number of moles of nitrogen given STP conditions (273 K and 1.00 atm). From PV = nRT, we can get n = PV/RT. Plugging in our values, and using 0.08206 L•atm/K•mol as our gas constant, R, we get n = (1.00)(846)/(0.08206)(273) = 37.8 moles, which confirms our answer.
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<h3>Ethyl 2-methyl-4-pentenoate by Malonic ester synthesis.</h3>

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