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3 years ago

How many moles of nitrogen are present at STP if the volume is 846L

1 answer:

3 0

A mole of any gas occupied 22.4 L at STP. So, the number of moles of nitrogen gas at STP in 846 L would be 846/22.4 = 37.8 moles of nitrogen gas.

Alternatively, you can go the long route and use the ideal gas law to solve for the number of moles of nitrogen given STP conditions (273 K and 1.00 atm). From PV = nRT, we can get n = PV/RT. Plugging in our values, and using 0.08206 L•atm/K•mol as our gas constant, R, we get n = (1.00)(846)/(0.08206)(273) = 37.8 moles, which confirms our answer.

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Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:

dem82 [27]

Answer:

The percent yield of the reaction is 62.05 %

Explanation:

Step 1: Data given

Volume of methane = 25.5 L

Pressure of methane = 732 torr

Temperature = 25.0 °C = 298 K

Volume of water vapor = 22.0 L

Pressure of H2O = 704 torr

Temperature = 125 °C

The reaction produces 26.0 L of hydrogen gas measured at STP

Step 2: The balanced equation

CH4(g) + H2O(g) → CO(g) + 3H2(g)

Step 3: Calculate moles methane

p*V = n*R*T

⇒with p = the pressure of methane = 0.963158 atm

⇒with V = the volume of methane = 25.5 L

⇒with n = the moles of methane = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 298 K

n = (p*V) / (R*T)

n = (0.963158 * 25.5 ) / ( 0.08206 * 298)

n = 1.0044 moles

Step 4: Calculate moles H2O

p*V = n*R*T

⇒with p = the pressure of methane = 0.926316 atm

⇒with V = the volume of methane = 22.0 L

⇒with n = the moles of methane = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 398 K

n = (p*V) / (R*T)

n = (0.926316 * 22.0) / (0.08206 * 398)

n = 0.624 moles

Step 5: Calculate the limiting reactant

For 1 mol methane we need 1 mol H2O to produce 1 mol CO and 3 moles H2

H2O is the limiting reactant. It will completely be consumed (0.624 moles).

Methane is in excess. There will react 0.624 moles. There will remain 1.0044 - 0.624 moles = 0.3804 moles methane

Step 6: Calculate moles hydrogen gas

For 1 mol methane we need 1 mol H2O to produce 1 mol CO and 3 moles H2

For 0.624 moles H2O we'll have 3*0.624 = 1.872 moles

Step 9: Calculate volume of H2 at STP

1.0 mol at STP has a volume of 22.4 L

1.872 moles has a volume of 1.872 * 22.4 = 41.9 L

Step 10: Calculate the percent yield of the reaction

% yield = (actual yield / theoretical yield) * 100 %

% yield = ( 26.0 L / 41.9 L) *100 %

% yield = 62.05 %

The percent yield of the reaction is 62.05 %

6 0

3 years ago

Read 2 more answers

A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper

Anit [1.1K]

Explanation:

Reaction equation for the given chemical reaction is as follows.

$2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}$

Equation for reaction quotient is as follows.

Q = $\frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}$

= $\frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}$

= 0.256

As, Q > K (= 0.12)

The effect on the partial pressure of $SO_{3}$ as equilibrium is achieved by using Q, is as follows.

This means that there are too much products.

Equilibrium will shift to the left towards reactants.

More $SO_{3}$ is formed.

Partial pressure of $SO_{3}$ increases.

4 0

3 years ago

7. Complete the concept map below.

Ilya [14]

Drainage that is not handled properly can cause an increase in erosion, changes in stormwater runoff, flooding, and damage to water quality.

<h3>Natural Disaster?</h3>

Large-scale geological or meteorological phenomena that have the potential to cause loss of life or property are considered natural disasters.
Tornadoes and severe storms are examples of these catastrophes. Tropical Storms and Hurricanes. Floods.
They release significant amounts of gas and dust into the atmosphere, particularly the upper atmosphere, which temporarily alters the climate on Earth.
Large volcanic eruptions should be followed by a drop in the average surface temperature, which is actually seen and lasts for typically 1 to 3 years.
Deforestation and the combustion of fossil fuels have detrimental environmental effects that directly affect the biosphere. Pollutant emissions and carbon dioxide have a negative impact on all types of life.

To learn more about Natural Disaster refer to:

brainly.com/question/13800641

#SPJ13

4 0

1 year ago

How much carbon would be needed to make 8.8g of carbon dioxide?<br>

PIT_PIT [208]

The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

44g/mole = 6.023 ※10^23 CO2 molecules

=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….

7 0

2 years ago

For the following SN2 reaction, draw the organic and inorganic products of the reaction, and identify the nucleophile, substrate

Sauron [17]

Answer:

Substrate:alkyl halide

Leaving group: Cl

Organic product: The nitrile

Inorganic product: Cl-

Nucleophile: CN-

Explanation:

An SN2 reaction is a concerted bimolecular reaction. Concerted means that it involves two reactions taking place at the same time while bimolecular means that the rate determining step involves two molecules. The cyanide ion attacks the alkyl halide from the rear. In the transition state, the leaving group (Cl-) is departing while the nucleophile (CN-) is forming a bond to the alkyl halide simultaneously. The alkyl halide is the substrate in the reaction. The organic product is the nitrile shown in the image attached.

3 0

3 years ago