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bekas [8.4K]
4 years ago
13

A straight line on a graph means there is a ______ relationship between the dependent variable and the independent variable.

Chemistry
2 answers:
coldgirl [10]4 years ago
8 0
Its a linear relationship
dangina [55]4 years ago
5 0
Proportional linear relationship
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Name the following chemical compound.
olya-2409 [2.1K]
A. sulfur dioxide ...................................................
8 0
4 years ago
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Arrange the following elements in order of increasing (from smallest to largest) atomic size: H, Br, Cl, O. Explain the reasonin
juin [17]

Explanation:

Atomic size is defined as the distance between the nucleus and valence shell of an atom. Valence shell is the outermost shell of an atom.

When we move across a period in a periodic table then there will occur a decrease in atomic size of the atoms. But when we move across a group in a periodic table then there will occur an increase in atomic size of the atom.

Hydrogen is a period 1 element, oxygen is a period 2 element, chlorine is a period 3 element and bromine is a period 4 element.

Therefore, given elements are arranged in order of increasing atomic size as follows.

                             H < O < Cl < Br  

5 0
3 years ago
What is the correct value using 3 significant figures for 14.8232 g/mol?
REY [17]

Answer:

14.8 g/mol

Explanation:

Starting on the left, count in 3 numbers (14.8), then round using the next number (0.02).

Because 2 is less than 5, the number stays the same and is not rounded up.

5 0
4 years ago
A student creates a solution by dissolving some Na2SO4 (molar mass = 142.05 g/mol) in enough water to create 0.500 L of solution
NeX [460]

Answer : The mass of Na_2SO_4 is, 4.43 grams.

Explanation :

As we know that, when Na_2SO_4 dissolve in water then it dissociates to give 2 mole of sodium ion Na^+ and 1 mole of sulfate ion SO_4^{2-}

The chemical reaction will be:

Na_2SO_4\rightarrow 2Na^++SO_4^{2-}

Thus, the concentration of Na_2SO_4 = \frac{\text{Concentration of }Na^+}{2}=\frac{0.125M}{2}=0.0625M

First we have to calculate the moles of Na_2SO_4

\text{Concentration of }Na_2SO_4=\frac{\text{Moles of }Na_2SO_4}{\text{Volume of solution}}

0.0625M=\frac{\text{Moles of }Na_2SO_4}{0.500L}

\text{Moles of }Na_2SO_4=0.0312mol

Now we have to calculate the mass of Na_2SO_4

\text{Mass of }Na_2SO_4=\text{Moles of }Na_2SO_4\times \text{Molar mass of }Na_2SO_4

Molar mass of Na_2SO_4 = 142 g/mol

\text{Mass of }Na_2SO_4=0.0312mol\times 142g/mol=4.43g

Thus, the mass of Na_2SO_4 is, 4.43 grams.

6 0
3 years ago
An electrochemical cell contains a standard hydrogen electrode and a cathode consisting of a metallic chromium electrode, Cr(s),
stira [4]

Answer:

c. I, II and III

Explanation:

The cell is as follows

Cr / Cr⁺²(1M) // H⁺ ( 1 M ) / H₂

Standard reduction potential of hydrogen cell is zero . Standard reduction potential is negative E for Cr⁺² / Cr(1M) half cell

Cell potential = Ecathode - Eanode

= 0 - ( - E)

= E

E is cell potential and also standard cell potential or emf of the cell .

Standard reduction potential that is for Cr3+/Cr.  is  - E .

Hence statement I , II , III are right . IV th statement is wrong because of sign

Option c is correct.

5 0
3 years ago
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