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Cerrena [4.2K]
3 years ago
7

The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16

cost reports for each of the two departments shows cost variances of 2.3 and 5.6, respectively. Is this sample sufficient to conclude that the two production departments differ in terms of unit cost variance? Use a = .10.
Calculate the value of the test statistic (to 2 decimals).

Mathematics
1 answer:
andreev551 [17]3 years ago
5 0

Answer:

Test Statistic is 2.34

Step-by-step explanation:

File Attached. kindly view it.

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Of the 114.2 million Americans who owned a TV, 94.2 million also owned a DVD player. What percent of those who owned a TV also o
Luda [366]

Answer:

82.5% Americans owned a TV also owned a DVD player .

Step-by-step explanation:

Formula

Percentage = \frac{Part\ value\times 100}{Total\ value}

As given

Of the 114.2 million Americans who owned a TV, 94.2 million also owned a DVD player.

Here

Part value = 94.2 million

Total value = 114.2 million

Putting all the values in the formula

Percentage = \frac{94.2\times 100}{114.2}

Percentage = \frac{94200\times 10}{1142\times 10}

Percentage = \frac{942000}{11420}

Percentage = 82.5 %

Therefore 82.5% Americans owned a TV also owned a DVD player .

3 0
3 years ago
(x^6z^9)(4xyz^9)(-5x^8y^6)
Mariana [72]
We can re arrange this:
(-5)*(4) * x^6 * x * x^8 * y * y^6 * z^9 * z^9

using exponent properties
we can get
-20 x^15 y^7 z^18
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3 0
3 years ago
Find the zeroes of polynomial x² -(√3+1)x+√3
r-ruslan [8.4K]
X² - √3x -x +√3

x(x-√3) -(x-√3)

(x-√3)(x-1)

zeroes are x-√3 = 0
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and x-1 =0
       x =1
6 0
3 years ago
Circle A has center of (6, 7), and a radius of 4 and circle B has a center of (2, 4), and a radius of 16. What steps will help s
VARVARA [1.3K]

Answer:

Circle A will be similar to circle B when circle A is dilated by a scale factor of 4.

4 0
3 years ago
Read 2 more answers
What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2 + 3x^2y^2 + 3x^4y?
WINSTONCH [101]

Given:

The polynomials are:

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

To find:

The completely simplified sum of the polynomials.

Solution:

We have,

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

The sum of given polynomials is:

Sum=3x^2y^2-2xy^5-3x^2y^2+3x^2y^2+3x^4y

Sum=-2xy^5+3x^4y+3x^2y^2

Therefore, the sum of the given polynomials is -2xy^5+3x^4y+3x^2y^2. It is a polynomial with degree 6 and leading coefficient -2.

5 0
3 years ago
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