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zvonat [6]
3 years ago
10

How deep would you have to drill to reach the center of earth?

Physics
1 answer:
EastWind [94]3 years ago
4 0

The radius of the Earth is about  3,960  miles.

That's how far the center of the Earth is straight down under your feet. 
It's farther than the distance all the way across the USA, from New York
to Los Angeles.  It's like the distance from London (England) to Chicago.

If you drill absolutely straight and aim straight down, that's how far
you need to drill to reach the center.  Unfortunately, your drill will melt
long before you get there.

The longest hole ever drilled into the Earth (so far) is the Sakhalin-I Oduptu Well,
drilled by Russia into the sea-bottom in 2011. 

That hole is 40,502 feet ... roughly 7.67 miles, or about  0.0019 of the distance
to the center of the Earth.  You can see that we still have quite a long way to go !

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______ is most resistant to thermal energy transfers. a. copper wire b. aluminum foil c. water d. foam insulation
Reika [66]

Answer:

Water

Explanation:

Because it does not conduct much energy.

8 0
3 years ago
Which of the Jovian planets have rings?
stira [4]
Jupiter , Saturn , Uranus , Neptune .
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A battery can provide a current of 1.80 A at 2.60 V for 6.00 hr. How much energy (in kJ) is produced?A battery can provide a cur
love history [14]

Answer:

The energy which is produced by a battery is 101.1 kJ.

Explanation:

The expression for the energy in terms of voltage, current and time is as follows;

E=VIt

Here, V is the voltage, I is the current and t is the time.

It is given in the problem that a battery can provide a current of 1.80 A at 2.60 V for 6.00 hr.

Calculate the energy of the battery.

E=VIt

Convert time from hour int seconds.

t=6 hr

t=(6)(60)(60)

t=21600 s

Put I= 1.80 A, V= 2.60 V and t= 21600 s in the expression of energy.

E=(2.60)(1.80)(21600)

E= 101.1 kJ

Therefore, the energy which is produced by a battery is 101.1 kJ.

4 0
3 years ago
A spring is originally 0.4m. When a 23N force is applied it stretches to a total of 0.7m. How far is the spring been extended? W
sergejj [24]

Recall the force applied to a spring and its extension/compression:

F = kΔx

Δx is the change in the spring's length (measured from its original length).

x = 0.7 m

x₀ = 0.4 m

Δx = x-x₀ = 0.7 m - 0.4 m = 0.3 m

F = 23 N


Substitute and solve for k:

23 = k×0.3

<h3>k = 7.67 N/m</h3>
8 0
3 years ago
A man standing in an elevator holds a spring scale with a load of 5 kg suspended from it. What would be the reading of the scale
mel-nik [20]

Answer:

3.1 kg

Explanation:

Applying,

R = m(g-a)..................... Equation 1

Where R = weight of the scale when the elevator is coming down, a = acceleration of the elevator, g = acceleration due to gravith.

From the question,

Given: m = 5 kg, a = 3.8 m/s²

Constant: g = 9.8 m/s²

Substitute these values into equation 1

R = 5(9.8-3.8)

R = 5(6)

R = 30 N

Hence the spring scale is

m' = R/g

m' = 30/9.8

m' = 3.1 kg

8 0
3 years ago
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