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3 years ago

How deep would you have to drill to reach the center of earth?

1 answer:

4 0

The radius of the Earth is about 3,960 miles.

That's how far the center of the Earth is straight down under your feet.
It's farther than the distance all the way across the USA, from New York
to Los Angeles. It's like the distance from London (England) to Chicago.

If you drill absolutely straight and aim straight down, that's how far
you need to drill to reach the center. Unfortunately, your drill will melt
long before you get there.

The longest hole ever drilled into the Earth (so far) is the Sakhalin-I Oduptu Well,
drilled by Russia into the sea-bottom in 2011.

That hole is 40,502 feet ... roughly 7.67 miles, or about 0.0019 of the distance
to the center of the Earth. You can see that we still have quite a long way to go !

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A traveling periodic wave passes a point of observation. At this point, the time between successive crests is 0.2s. What can you

Aleks04 [339]

The time between the successive crusts will give the time period of the wave.

So, the time period, T of the given wave is 0.2 s.

The frequency of a wave is the reciprocal of its time period. That is,

Frequency, ν = $\frac{1}{T}$

= $\frac{1}{0.2}$

= 5 Hz

Thus, the frequency of the given travelling periodic wave is 5 Hz.

3 0

3 years ago

Read 2 more answers

You have a match and you enter a wagon with a candle, a lamp and a fireplace. Which one do you light first?

NikAS [45]

You light the match :)

8 0

3 years ago

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Imagine a raindrop starting from rest in a cloud 2 km in the air. If it fell with no air friction at all, it would accelerate to

LenKa [72]

Answer:

2) 433 mph

Explanation:

The final velocity of the raindrop as it reaches the ground can be found by using the equation for a uniformly accelerated motion:

$v^2 = u^2 + 2ad$

where

v is the final velocity

u = 0 is the initial velocity (the raindrop starts from rest)

a = g = 9.8 m/s^2 is the acceleration due to gravity

d = 2 km = 2000 m is the distance covered

Solving for v,

$v=\sqrt{u^2 +2gd}=\sqrt{0^2+2(9.8 m/s^2)(2000)}=198 m/s$

And keeping in mind that

1 mile = 1609 metres

1 hour = 3600 s

The speed converted into miles per hour is

$v=198 \frac{m}{s}\cdot \frac{3600 s/h}{1609 m/mi}=433 mph$

5 0

3 years ago

A block of mass 1.3 kg is resting at the base of a frictionless ramp. A bullet of mass 50 g is traveling parallel to the ramp su

aleksandrvk [35]

Answer:

s = 2.65 m

Explanation:

given,

mass of block,M = 1.3 Kg

mass of bullet,m = 50 g = 0.05 Kg

speed of bullet,u = 250 m/s

speed of bullet after collision,v = 100 m/s

distance traveled by the block = ?

Assuming the angle of inclination of ramp equal to 40°

calculating the speed of the block

using conservation of momentum

M u' + m u = m v + M v'

initial speed of the block is equal to zero

0 + 0.05 Kg x 250 = 0.05 x 100 + 1.3 x v'

1.3 v' = 7.5

v' = 5.77 m/s

now, calculation of acceleration

equation the horizontal component

-mg sin θ = ma

a = - g sin θ

a = - 9.8 x sin 40°

a = -6.29 m/s²

using equation of motion for the calculation of distance moved by the block

v² = u² + 2 a s

0² = 5.77² + 2 x (-6.29) x s

12.58 s = 33.29

s = 2.65 m

hence, the distance moved by the block is equal to 2.65 m

3 0

3 years ago

What happens if the breakdown voltage is exceeded.

s2008m [1.1K]

Answer:

this may help

Explanation:

maybe it will cause the eletric cause a fire that will mean it will spread till the fire men should come

7 0

3 years ago