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zvonat [6]
3 years ago
10

How deep would you have to drill to reach the center of earth?

Physics
1 answer:
EastWind [94]3 years ago
4 0

The radius of the Earth is about  3,960  miles.

That's how far the center of the Earth is straight down under your feet. 
It's farther than the distance all the way across the USA, from New York
to Los Angeles.  It's like the distance from London (England) to Chicago.

If you drill absolutely straight and aim straight down, that's how far
you need to drill to reach the center.  Unfortunately, your drill will melt
long before you get there.

The longest hole ever drilled into the Earth (so far) is the Sakhalin-I Oduptu Well,
drilled by Russia into the sea-bottom in 2011. 

That hole is 40,502 feet ... roughly 7.67 miles, or about  0.0019 of the distance
to the center of the Earth.  You can see that we still have quite a long way to go !

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Sunlight is reflected off of a puddle of water ahead of a driver. The index of refraction of the water is 1.333. If a driver sit
Lynna [10]

Answer:

option C is correct

distance from the driver is 2 m

Explanation:

Given data

index of refraction of the water n = 1.333

driver height from ground=  1.5 m

to find out

What angle does light become maximally polarized and what distance from the driver will polarized

solution

we know that n1 for water = 1.33 and we know for air n2 = 1

so  tan(θ)  = n1 / n2

tan(θ)  = 1.33 / 1

so (θ) = 53.06 degree

so for distance d will be calculate as

tan ( 90 - (θ) ) = height / distance

tan ( 90 - 53.06 ) = 1.5 / distance

distance = 1.5 / 0.7519

distance = 1.994 m  = 2 m

so option C is correct

distance from the driver is 2 m

5 0
3 years ago
A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.40 kg box that is sitting on the horizontal,
Fynjy0 [20]

Answer:v=7.24 m/s

Explanation:

Given

F(x)=18-0.530 x

mass m=8.40 kg

box is at rest at x=0

Distance traveled=16 m

mv\frac{\mathrm{d} v}{\mathrm{d} x}=F=\left ( 18-0530x\right )dx

\int_{0}^{v}vdv=\int_{0}^{16}\left ( 18-0.530x\right )dx

\frac{mv^2}{2}=\left ( 18x-0530\frac{x^2}{2}\right )_0^{16}

v^2=\frac{288-67.841\times 2}{8.40}

v=7.24 m/s

6 0
3 years ago
How is Uranus colder than Neptune
STatiana [176]
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4 0
3 years ago
Mr. Llama walked from his house to the bus stop. The bus stop is 2 miles from his house. He returned back to his house from the
Hoochie [10]

Answer:

Displacement of Mr. Llama: Option D. 0 miles.

Explanation:

The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.

For Mr. Llama:

  • Final position: Mr. Llama's house;
  • Initial position: Mr. Llama's house.

The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.

7 0
3 years ago
Two toddlers are fighting over a toy. Joey pulls the toy with a force of 8 N while Tommy pulls the toy with a force of 7.5 N. Wh
Firdavs [7]

Answer:

15.5 and Joey will get the toy

Explanation:

Net force is all the forces acting on the object and since Joey is pulling .5 newtons more he will get the toy.

5 0
3 years ago
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