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The molar extinction coefficient is 15,200 .
The formula to be used to calculate molar extinction coefficient is -
A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.
The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.
Rewriting the formula as per molar extinction coefficient -
ξ =
ξ =
Performing multiplication in denominator to find the value of molar extinction coefficient
ξ =
Performing division to find the value of molar extinction coefficient
ξ = 15,200
Hence, the molar extinction coefficient is 15,200 .
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Question:
Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the same as pure water at 20.0 degrees C (18 torr). The volume of the mixture is 1.7 L and its total pressure is 0.987 atm. Determine the number of moles of hydrogen gas present in the sample.
A. 0.272 mol
B. 0.04 mol
C. 0.997 mol
D. 0.139 mol
E. 0.0681 mol
Answer:
The correct option is;
E. 0.0681 mol
Explanation:
The equation for the reaction is
Zn + HCl = H₂ + ZnCl₂
Vapor pressure of the liquid = 18 torr = 2399.803 Pa
Total pressure of gas mixture H₂ + liquid vapor = 0.987 atm
= 100007.775 Pa
Therefore, by Avogadro's law, pressure of the hydrogen gas is given by the following equation
Pressure of H₂ = 100007.775 Pa - 2399.803 Pa = 97607.972 Pa
Volume of H₂ = 1.7 L = 0.0017 m³
Temperature = 20 °C = 293.15 K
Therefore,
Therefore, the number of moles of hydrogen gas present in the sample is n ≈ 0.0681 moles.
Answer:moles or atom. The SI base unit for amount of substance is the mole. 1 mole is equal to 6.0221415E+23 atom. Note that rounding errors may occur, so always check the results.
Explanation:
Answer:
The correct option is: B) 2nd order
Explanation:
The rate law equation of a chemical reaction is a mathematical expression which expresses the relationship of the rate of the chemical reaction with concentration of reactants. The overall order of the reaction is equal to the sum of orders with respect to all the reactants in the rate law equation.
The given reaction: NO(g) + O₃(g) → NO₂(g) + O₂(g)
Rate = k[NO][O₃]
Therefore, the given chemical reaction is second order.