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jolli1 [7]
3 years ago
10

What are the radicals?Write their types with four examples.​

Chemistry
2 answers:
polet [3.4K]3 years ago
4 0

Answer:

<h3>A<em><u> group of atoms behaving as a unit in a number of compounds.</u></em><em><u> </u></em></h3>

Explanation:

<h2><em><u>Sorry</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>giving </u></em><em><u>half</u></em><em><u> </u></em><em><u>a</u></em><em><u>nswer</u></em><em><u> </u></em><em><u> </u></em><em><u>only</u></em><em><u> </u></em><em><u>.</u></em><em><u>I</u></em><em><u> </u></em><em><u>known </u></em><em><u>this</u></em><em><u> </u></em><em><u>much</u></em><em><u> </u></em><em><u>only</u></em><em><u>.</u></em></h2><h2><em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>U</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>answer </u></em><em><u>and</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>help </u></em><em><u>u</u></em><em><u>.</u></em></h2>
alina1380 [7]3 years ago
3 0

Answer:

<h3>A radical is a chemical entity with an unpaired electron in it. A radical can be electrically neutral, radical cation charged positively, or radical anion charged negatively. The Radicals Examples. ... In ultraviolet light the chlorine molecule Cl2 undergoes homolysis to form two radicals of Cl.</h3>

<h2>OR </h2>

<h3>Radicals : A radical is an atom of an element or a group of atoms of different elements that behaves as a single unit with a positive or negative charge on it. Valency : It is the number of electrons donated or accepted by the valence shell of an atom during chemical combination.</h3>

<h2>Example </h2>

<h3>: Some common examples of basic radicals are Na+, Ba2+, Fe3+ etc. Composite Radicals-Acetylimino, Cyclohexane carbonyl etc. Bivalent Acidic Radicals-The ion formed after removal of Hydrogen ion from an acid is called as Acidic Radical.</h3>

HOPE ITS CLEAR. ☺️

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What is the process used to convert between moles, mass, volume, and particles?
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conversion between mass and moles#

<em> </em>

<em>A substance's molar mass is calculated by multiplying its relative atomic mass by the molar mass constant (1 g/mol). The molar mass constant can be used to convert mass to moles. By multiplying a given mass by the molar mass, the amount of moles of the substance can be calculated.</em>

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2 years ago
Assuming the volumes are additive, what is the [Cl−] in a solution obtained by mixing 297 mL of 0.675 M KCl and 664 mL of 0.338
Elden [556K]

<u>Answer:</u> The concentration of chloride ions in the solution obtained is 0.674 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

  • <u>For KCl:</u>

Molarity of KCl solution = 0.675 M

Volume of solution = 297 mL

Putting values in equation 1, we get:

0.675=\frac{\text{Moles of KCl}\times 1000}{297}\\\\\text{Moles of KCl}=\frac{(0.675mol/L\times 297)}{1000}=0.200mol

1 mole of KCl produces 1 mole of chloride ions and 1 mole of potassium ion

Moles of chloride ions in KCl = 0.200 moles

  • <u>For magnesium chloride:</u>

Molarity of magnesium chloride solution = 0.338 M

Volume of solution = 664 mL

Putting values in equation 1, we get:

0.338=\frac{\text{Moles of }MgCl_2\times 1000}{664}\\\\\text{Moles of }MgCl_2=\frac{(0.338mol/L\times 664)}{1000}=0.224mol

1 mole of magnesium chloride produces 2 moles of chloride ions and 1 mole of magnesium ion

Moles of chloride ions in magnesium chloride = (2\times 0.224)=0.448mol

Calculating the chloride ion concentration, we use equation 1:

Total moles of chloride ions in the solution = (0.200 + 0.448) moles = 0.648 moles

Total volume of the solution = (297 + 664) mL = 961 mL

Putting values in equation 1, we get:

\text{Concentration of chloride ions}=\frac{0.648mol\times 1000}{961}\\\\\text{Concentration of chloride ions}=0.674M

Hence, the concentration of chloride ions in the solution obtained is 0.674 M

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