Answer:
Speed of the this part is given as
Also the direction of the velocity of the third part of plate is moving along 135 degree with respect to one part of the moving plate
Explanation:
As we know by the momentum conservation of the system
we will have
here we know that
the momentum of two parts are equal in magnitude but perpendicular to each other
so we will have
now from above equation we have
Also the direction of the velocity of the third part of plate is moving along 135 degree with respect to one part of the moving plate
STP stands for standard temperature and pressure. <span>The standard temperature is 273 K (0° Celsius or 32° Fahrenheit) and the standard pressure is 1 atm pressure. Also, at this condition 1 mole of a substance is equal to 22.4 L.Therefore, the first and the third options are the correct ones.</span>
Answer:
<h2>The answer is 8075 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
<h3>force = mass × acceleration</h3>
From the question
mass = 1.7 × 10³ kg = 1700 kg
acceleration = 4.75 m/s²
We have
force = 1700 × 4.75
We have the final answer as
<h3>8075 N</h3>
Hope this helps you
The initial velocity of go-kart is 2.5 m/s.
<u>Explanation:</u>
Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.
In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.
As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.
Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,
Initial velocity = 0.5 × 5 = 2.5 m/s.
So the initial velocity of go-kart is 2.5 m/s.
