Answer:
A. Two tennis balls that are near each other
Explanation:
The formula for gravitational force (F) between two objects is
where m₁ and m₂ are the masses of the two objects, d is the distance between their centres, and G is the gravitational constant.
Thus, two objects that are far from each other will have a smaller gravitational force. We can eliminate Options C and D.
If the objects are at the same distance, those with the smaller mass will have a smaller force.
The mass of a tennis ball is 57 g.
The mass of a soccer ball is 430 g.
Two tennis balls that are near each other will have a smaller gravitational attraction.
F = ma, where m = mass in kg, a = acceleration in m/s², F = Force in Newton
F = 1 * 2
F = 2 N
Force needed is 2 Newtons.
Answer:
La fuerza que será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s² es 80 N.
Explanation:
La segunda ley de Newton, llamada ley fundamental o principio fundamental de la dinámica, plantea que un cuerpo se acelera si se le aplica una fuerza.
De esta manera, esta ley establece que las aceleraciones que experimenta un cuerpo son proporcionales a las fuerzas que recibe. Dicho de otra forma, la aceleración de un cuerpo es proporcional a la fuerza neta que se le aplica. Cuanto mayor es la fuerza que se le aplica a un objeto con una masa dada, mayor será su aceleración.
La segunda Ley de Newton se expresa matemáticamente como:
F = m*a
Donde:
-
F es la fuerza neta. Se expresa en Newton (N)
- m es la masa del cuerpo. Se expresa en kilogramos (Kg.).
- a es la aceleración que adquiere el cuerpo. Se expresa en metros sobre segundo al cuadrado (m/s²).
En este caso:
Reemplazando:
F= 20 kg* 4 m/s²
Resolviendo:
F= 80 N
<u><em>La fuerza que será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s² es 80 N.</em></u>
The formula to use is: I = (<span> ΔV / R )
Once you solve for R, your new formula would be: R= (</span><span> ΔV / I )
Plug in your values to get: R = (1.5V / .75A )
Finally, R = 2</span><span>Ω</span>
The time when the cheetah catches up with the widebeest is 1.53 s
If the initial separation distance approaches zero, it will take the cheetah 1.05 s to catch the widebeest.
The given parameters;
- speed of the wildebeest calf, Vw = 10 m/s
- distance traveled by the calf before the cheetah stands up = 7 m
- constant acceleration of the cheetah, a = 9.5 m/s²
Let the speed of the cheetah = Vc
let the time the cheetah catches up with the wildebeest = t
Apply relative velocity formula to determine the time when the cheetah catches up with the widebeest;
Assuming the wildebeest and the cheetah are running in the same direction;
The time when the cheetah catches up with the widebeest is 1.53 s
If the initial separation distance approaches zero;
Thus, if the initial separation distance approaches zero, it will take the cheetah 1.05 s to catch the widebeest.
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