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Lelechka [254]
4 years ago
15

An accepted value for the acceleration due to gravity is 9.801 m/s2. In an experiment with pendulums, you calculate that the val

ue is 9.4 m/s2. Should the accepted value be tossed out to accommodate your new finding? Explain.
Physics
1 answer:
Fed [463]4 years ago
5 0

g Generally the accepted value of acceleration due to gravity is 9.801 m/s^2

as per the question the acceleration due to gravity is found to be 9.42m/s^2 in an experiment performed.

the difference between the ideal and observed value is 0.381.

hence the error is -\frac{0.381}{9.801} *100

                                                            =3.88735 percent

the error is not so high,so it can be  accepted.

now we have to know why this occurs-the equation of time period of the simple pendulum is give as-T=2\pi\sqrt[2]{l/g}

                                                      g=4\pi^2\frac{l}{T^2}

As the experiment is done under air resistance,so it will affect to the time period.hence the time period will be more which in turn decreases the value of g.

if this experiment is done in a environment of zero air resistance,we will get the value of g which must be approximately equal to 9.801  m/s^2

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pav-90 [236]

Answer:

the unloaded braking efficiency is 84.6 %

Explanation:

Given the data in the question;

by Ignoring aerodynamic resistance; we can find the theoretical stopping distance using the following formula

S = (Y_{b}( V₁² - V₂²)) / ( 2g( ηbμ + f_{rl} ± sin∅_{g}))

now given that the tracked is levelled, ∅_{g} = 0, also Y_{b} = 1.04 for level or flat road

Speed V₁ = 60mil/hr = (60×5280)/(1×60×60) = 316800ft/3600s = 88ft/s

now, we substitute in our values to get the braking efficiency;

180ft = (1.04( (88ft/s)² - 0²)) / ( 2(32.2( (ηb/100)(0.80) + (0.018) ± sin(0°)))

180ft = 8053.76 / ( 64.4)(0.008ηb + 0.018)

180ft = 8053.76 / ( 0.5152ηb + 1.1592)

180( 0.5152ηb + 1.1592)  = 8053.76

( 0.5152ηb + 1.1592) = 8053.76 /180

0.5152ηb + 1.1592 = 44.7431

0.5152ηb = 44.7431 - 1.1592

0.5152ηb = 43.5839

ηb = 43.5839 / 0.5152

ηb = 84.596 ≈ 84.6 %

Therefore,  the unloaded braking efficiency is 84.6 %

7 0
3 years ago
Consider a basketball player spinning a ball on the tip of a finger. If a player performs 1.99 J of work to set the ball spinnin
scoundrel [369]

To solve this problem it is necessary to apply the concepts related to rotational kinetic energy, the definition of the moment of inertia for a sphere and the obtaining of the radius through the circumference. Mathematically kinetic energy can be given as:

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I = Moment of inertia

\omega = Angular velocity

According to the information given we have that the radius is

\Phi= 2\pi r

0.749m = 2\pi r

r = 0.1192m

With the radius obtained we can calculate the moment of inertia which is

I = \frac{2}{3}mr^2

I = \frac{2}{3}(0.624)(0.1192)^2

I = 5.91*10^{-3} kg \cdot m^2

Finally, from the energy equation and rearranging the expression to obtain the angular velocity we have to

\omega = \sqrt{\frac{2KE}{I}}

\omega = \sqrt{\frac{2(1.99)}{5.91*10^{-3}}}

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Answer:

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Therefore, if we want to see how does the period of the pendulum on Mars change compared to the one on Earth, we can do the ratio between the two of them:
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