Image<span> formed by a </span>plane mirror is<span> always </span>virtual<span> which means that the light rays </span>do<span> not actually come from the </span>image but<span> upright and these of the same shape and size are the object it </span>is<span> reflecting.</span>
Answer:
I chose c because it is the greater slope at point c
A thunder bolt and lightning strike wouldn't do anyone any favours and might well account for the mess and the broken windows ...
Since no external torques are acting on the skater, his angular momentum must be conserved in the two different situations (arms and legs in - arms out and one leg out). The angular momentum is given by
where I is the moment of inertia and
the angular speed.
Labeling with "1" the situation where the skater has arms and legs in, and with "2" the situation where the skater has arms out and one leg out, the conservation of the angular momentum becomes
or
We know the moment of inertia and the angular speed of the skater when he has arms and legs in:
and also the moment of inertia of the skater when he has arms and one leg out:
so we can find his angular speed when he opens the arms and one leg:
1) D.
2) C. (or) D.
This should be the answer if I remember correctly hope it helps