Answer:
a. 10 Amps
b. 22 Ohms
c. 220 kW·h
d. $13.2
Explanation:
a. The question is with regards electric power, "P", which is given as follows;
P = I × V
Where;
P = The power generated by electric current
I = The current flowing in the circuit (through the resistance, R)
V = The voltage in the circuit
The given parameters of the electric oven are;
The resistance of the electric oven = R
The power consumed by the electric oven, P = 2200 W
The voltage at which the electric oven is working, V = 220 V
Therefore, from the equation for power, P = I × V, we have;
I = P / V
Therefore, we have;
I = 2,200 W/(220 V) = 10 Amps
b. The velocity, V = I × R
Where;
I = The current flowing
R = The resistance of the circuit
By making "R" the subject of the equation for voltage, "V", we have;
R = V/I = 220 V/(10 A) = 22 Ohms
c. The number of hours per day the resistor is used = 4 hours
The number of hours the resistor is used in 1 month (30 days) = 30 × 4 hours, t = 120 hours
The electric energy, E = P × t = 2200 W × 120 h = 220000 W·h = 220 kW·h
d. If electric energy costs, C = 0.06$/kW·h
Therefore, the cost to operate the electric oven during 1 month = 0.06$ × 220 kW·h = $13.2
