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Elan Coil [88]
3 years ago
11

A 3.5 kg wooden block is pulled with 12.5 N of force across a rough surface. If the force of friction is 4.8 N, find the net for

ce and the acceleration of the block. (Start by drawing a force diagram.)
Physics
1 answer:
Vesnalui [34]3 years ago
3 0

Answer:

F = 7.7 [N]

a = 2.2 [m/s²]

Explanation:

In the attached picture we see the forces on the wooden block, the total force is obtained by means of the sum of the pushforce and the friction force.

F_{total}=12.5-4.8\\F_{total}=7.7[N]

Now we must apply Newton's second law, which tells us that the total force on the body must be equal to the product of mass by acceleration.

F=m*a

7.7=3.5*a\\a=2.2[m/s^{2} ]

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<h3><u> Explanation: </u></h3>

Sunrise, sunset and night time are parts of the day with minimal or absolutely no presence of sunlight. To safely navigate roads, we require enough light in order to detect presence of other vehicles, signs and pedestrians. Less sunlight during sunrise and sunset light the sky but makes the roads and vehicles have a darker, less bright view. The contrast between colours is the least, making it difficult to identify objects and see clearly.  

A rising or a setting sun can also lead to glares on the driver’s view and thus obstruct it. Since a change in ambient light is observed, our eyes need to adjust with this change and this isn’t spontaneous. Night time driving has headlight glares from approaching vehicles and reduced surrounding visibility. The eyes switching for vision adaptability from dark to bright light if vehicles approach and pass by is not a quick action. Hence the driver’s vision is compromised in every such case and this may lead to accidents.  

7 0
4 years ago
A tennis ball is dropped from 1.16 m above the
sweet-ann [11.9K]

Answer:

Vf = 4.77 m/s

Explanation:

During the downward motion we can easily find the final velocity or the velocity with which the ball hits the ground, by using third equation of motion. The third equation of motion is given as follows:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height = 1.16 m

Vf = Final Velocity of Ball = ?

Vi = Initial Velocity of Ball = 0 m/s (Since, ball was initially at rest)

Therefore, using these values in the equation, we get:

(2)(9.8 m/s²)(1.16 m) = Vf² - (0 m/s)²

Vf = √(22.736 m²/s²)

<u>Vf = 4.77 m/s</u>

6 0
3 years ago
What is the classification of the reaction shown in the equation below?
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Answer:

d

Explanation:

because is a reducing agent, O 2 is an oxidizing agent.

6 0
2 years ago
g In a cold rolling operation, steel sheets that are initially 300 cm long X 80 cm wide X 8 cm thick are cold worked to 80 cm wi
seropon [69]

Answer:

100% cold working performed on this steel

Explanation:

Using the constant volume assumption:

                L₀W₀t₀ (initial)                                    =                      Lₐ Wₐ tₐ (final)

thus 300 cm long X 80 cm wide X 8 cm thick =   Lₐ x 80 cm wide X 5 cm thick

Lₐ = 300 cm long X 80 cm wide X 8 cm thick/80 cm wide X 5 cm thick

  =480 cm

% cold working performed on this steel = Lₐ Wₐ tₐ (final) /  L₀W₀t₀ (initial) 8 100

= 480 x 80 x 5/ 300 x 80 x 8 *100 = 100%

6 0
3 years ago
Using a diagram explain how acceleration can be obtained from a velocity time graph​
Oksi-84 [34.3K]

Answer:

For any v-t graph the acceleration is the slope of the graph. For average acceleration in a time period ‘t’ consider the change in velocity in time t and divide it by the time t. For instantaneous acceleration you need to go into the realm of differential calculus.

Explanation:

I hope this helps! I would really appreciate it if you would please mark me brainliest! Have a blessed day!

3 0
3 years ago
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