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Elan Coil [88]
3 years ago
11

A 3.5 kg wooden block is pulled with 12.5 N of force across a rough surface. If the force of friction is 4.8 N, find the net for

ce and the acceleration of the block. (Start by drawing a force diagram.)
Physics
1 answer:
Vesnalui [34]3 years ago
3 0

Answer:

F = 7.7 [N]

a = 2.2 [m/s²]

Explanation:

In the attached picture we see the forces on the wooden block, the total force is obtained by means of the sum of the pushforce and the friction force.

F_{total}=12.5-4.8\\F_{total}=7.7[N]

Now we must apply Newton's second law, which tells us that the total force on the body must be equal to the product of mass by acceleration.

F=m*a

7.7=3.5*a\\a=2.2[m/s^{2} ]

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From the list above, it is easy to see that the equation that best suits our purpose here is V_{fy} = V_{iy} + a_{y}t

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