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gtnhenbr [62]
3 years ago
9

Why the efficiency of an engine cannot be 100%?

Physics
2 answers:
Marysya12 [62]3 years ago
6 0
<span>No machine can operate at 100 percent efficiency because some of the energy input will always be used to overcome the force of gravity and the effects of friction and air resistance.</span>
Alex73 [517]3 years ago
3 0
No, because the engine can't convert enough heat. 100%? That's way too much. That is theoretically impossible. Its important to consider the equation, this will give you the better picture as to why it can't be. In fact, the maximum efficiency CANNOT be more than the Carnot limit. Its the 2nd Law of Thermodynamics. 
nth ≤ 1 - (Tc/Th) 

I hope this helped.
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A steam turbine operates at a boiler temperature of 450 k and an exhaust temperature of 300 k. what is the maximum theoretical e
Helga [31]
The maximum theoretical efficiency of the system is the one corresponding to the efficiency of a Carnot cycle operating between the same temperatures of the system:
\eta=1- \frac{T_c}{T_h}
where T_c and T_h are the cold and hot temperatures, respectively.
In our problem, T_c=300 K and T_h=450 K, therefore the maximum theoretical efficiency is
\eta=1- \frac{300 K}{450 K}=0.33
So, 33%.
5 0
3 years ago
Question : Is it possible for heat to transfer from T3 to T1 and why?
fomenos

Answer:

no its a negative

Explanation:

because they both are positive

6 0
4 years ago
A star with a mass like the Sun which will soon die is observed to be surrounded by a large amount of dust and gas -- all materi
Dafna11 [192]

Answer: D. Infrared

Infrared is the best way to observe it.

5 0
3 years ago
Is a single property such as density sufficient to always correctly identify a substance?
bazaltina [42]
Not at all. Density on its own is not sufficient
7 0
3 years ago
What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The spe
Eduardwww [97]

Answer:

Final temperature, T_f=21.85^{\circ}

Explanation:

Given that,

Mass of silver ring, m = 4 g

Initial temperature, T_i=41^{\circ}C

Heat released, Q = -18 J (as heat is released)

Specific heat capacity of silver, c=0.235\ J/g\ C

To find,

Final temperature

Solution,

The expression for the specific heat is given by :

Q=mc\Delta T

Q=mc(T_f-T_i)

T_f=\dfrac{-Q}{mc}+T_i

T_f=\dfrac{-18}{4\times 0.235}+41

T_f=21.85^{\circ}

So, the final temperature of silver is 21.85 degrees Celsius.

5 0
3 years ago
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