Answer:
the initial velocity of bullet is u = 330.335 m /s
Explanation:
given,
mass of bullet(m) = 7 g
Mass of pendulum ( M ) = 1.5- kg
The bullet emerges from the block with a speed (V) = 200 m/s
The maximum height ( h ) = 12 cm.
Let the initial speed of the bullet be ' u '
Apply, Law of conservation of momentum :
m u = ( m + M ) V ...............................(1)
Apply, Law of conservation of Energy :
...............(2)
From equation (1) and equation (2) , we have
But V = √2gh
u = 330.335 m /s
hence, the initial velocity of bullet is u = 330.335 m /s
The acceleration is 
Explanation:
This is a uniformly accelerated motion (constant acceleration), therefore we can apply the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the scooter in this problem, we have
u = 0 (it starts from rest)
v = 10.0 m/s is the final velocity
t = 4.0 s is the time interval
Solving for a, we find the acceleration:
Learn more about acceleration:
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Answer:
Change the wavelength to half while keeping velocity constant or change the wave velocity to 2 times while keeping wavelength constant.
Explanation:
The frequency of a wave can be defined as the rate of change of wave speed with respect to the wavelength of the wave.
Mathematically,
Here, v is the velocity, lambda is the wavelength, and f is the frequency of the wave.
If the observer want to double the frequency of the wave, then he should increase the wave velocity two times and take wavelength constant for this case or either he should half the wavelength of the wave to take the velocity of the wave constant.
Answer:
a) Team A will win.
b) The losing team will accelerate towards the middle line with 0.01 m/
Explanation:
Given that Team-A pulls with a force , 
and Team-B pulls with a force , 
∵ 
The rope will move in the direction of force 
.
∴ Team-A will win.
b) Considering both the teams as one system of total mass , 
Net force on the system , 
= 50-45 = 5N
Applying Newtons first law to the system ,
F = ma , where 'a' is the acceleration of the system.
Since , both the teams are connected by the same rope , their acceleration would be the same.
∴ 5 = 499×a
∴ a = 0.01 m/
Water evaporates at 100⁰C
So change in temperature = 100-20 = 80⁰C
Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg
Specific heat of water is 1 calorie/gram ⁰C = 4.186 joule/gram =4186 J/kg
So heat required E = mcΔT = 1 * 4186 *80= 334880 J =334.88 kJ
So amount of heat require to evaporate water = 334.88 kJ
