Answer:
velocity = 10 m/sec in the same direction as the first body did
Explanation:
The momentum of the body can be calculated as follows:
momentum = mass * velocity
For the first body, we have:
mass = 5 kg
velocity = 2 m/sec
momentum = mass * velocity
momentum = 5 * 2 = 10 kg.m/sec
We know that this momentum is transferred completely to the second body
For the second bode, we have:
momentum = 10 Kg.m/sec
mass = 1 kg
momentum = mass * velocity
10 = 1 * velocity
velocity = 10/1
velocity = 10 m/sec
Finally, we should get the direction of the motion:
Both the velocity of the first and second bodies have positive values. Therefore, the second body is moving in the same direction as the first body did.
Hope this helps :)
Answer:
-18y=1
Step-by-step explanation:
Sorry if this is wrong, I was just guessing...
Answer:
x = 12, x = 7
Step-by-step explanation:
The 2 legs of the triangle are congruent, both 2x + 7, then
2x + 7 + 2x + 7 + x + 11 = 85 ← equation for perimeter
5x + 25 = 85 ( subtract 25 from both sides )
5x = 60 ( divide both sides by 5 )
x = 12
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Opposite sides are congruent, then
2(2x) + 2(5x + 3) = 104 ← distribute and simplify both sides
4x + 10x + 6 = 104
14x + 6 = 104 ( subtract 6 from both sides )
14x = 98 ( divide both sides by 14 )
x = 7
Answer:
<em>5 boys play all the two games</em>
<em>25 boys play only one game</em>
Step-by-step explanation:
<u>Sets</u>
There are two sets defined in the question: one for the boys who play hockey (H) and the other for the boys who play volleyball (V).
All the boys play at least one of the two games, so no elements are outside both sets.
There are 30 boys in total. 20 of them play hockey and 15 play volleyball. Since the sum of both numbers is greater than the total of boys, the difference corresponds to the boys who play both games.
Thus 20 + 15 - 30 = 5 boys play both games
Given that 5 boys are shared by both sets, from the 20 playing hockey, 15 play ONLY hockey. From the 15 boys playing volleyball, 10 play ONLY volleyball.
Thus 15 + 10 = 25 boys play only one game.
The Venn diagram is shown in the image.
