Answer:
The correct option is A....
Step-by-step explanation:
Look at the attached picture:
A=(4,7)
B=(7,4)
The standard form of circle equation is:
(x-h)^2 +(y-k)^2 = r^2
Here h and k is the centre which is (4,4)
radius = 7-4 = 3
Now use the formula to find the answer:
(x-h)^2 +(y-k)^2 = r^2
(x - 4)^2 + (y - 4)^2 = 3^2
If we expand the formula we get:
x^2 - 8x + 16 + y^2 - 8y + 16 = 9
x^2 - 8x + y^2 - 8y + 23 = 0
Thus the correct option is A....
Answer:
The degree of the term is 5
Don't forget to mark me as brainliest
A. that is b^2-4ac
for
ax^2+bx+c
the deterimant (part under the radicand)
is b^2-4ac
if it is
1. less than 0 then there are no real solutions
2. eqal to 0 then there is 1 real solution
3. greater than 0, there are 2 real roots
9x^2-16x+60
b^2-4ac=(-16)^2-4*9*60=256-2160<0
no real solutions
B. grouping
ac method
4 times -5=-20
what 2 numbers multiply to get -20 and add to get 8?
-2 and 10
seperate the middle number to get that
4x^2-2x+10x-5=0
(4x^2-2x)+(10x-5)=0
2x(2x-1)+2(2x-1)=0
(2x-1)(2x+2)=0
set equal to 0
2x-1=0
2x=1
x=1/2
2x+2=0
2x=-2
x=-1
x=1/2 or -1
When you solve an equation, it has an equal sign (=) and inequalities do not. When you solve an inequality the answer isn't exact (depending on the sign ie: <, >, etc...) equations usually are exact answers. other than that, I don't think there is a big difference in solving them.
4c6d3 x 3c4d
4 x 3=12
12c
you add the powers so 6+4=10
12c10
d3 x d=d3
12c10d3
that is the answer i think
