Which of the following would be the most difficult to compress?

The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests tha

lakkis [162]

Answer:

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

Explanation:

Volume of the radiator = 3.6 L

Percentage of antifreeze = 60%

Total volume of anti freeze in radiator = 60% of 3.6 L :

$\frac{60}{100}\times 3.6 = 2.16 L$

Percentage of water= 40%

Given,optimal cooling of the engine is obtained with only 50% antifreeze.

So, now we want to reduce the percentage of antifreeze from 60% to 50 %

Volume of coolant removed = x

Volume of water added = x

Volume of anti freeze removed = 60% of(x) = 0.6x

Volume of antifreeze left in radiator =50% of 3.6 L = $\frac{50}{100}\times 3.6=1.8 L$

1.8 Liter is the desired volume of the antifreeze.

Total volume - Removed volume = desired volume

2.16 L - 60% of( x) = 1.8 L

$2.16 L-0.6x=1.8 L$

$x=\frac{2.16 l- 1.8 L}{0.6}=0.6 L$

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

4 0

4 years ago

Which of the following best explains why solids do not

timama [110]

What do you mean by ‘which of the following’? Without that I am not able to answer the question

7 0

3 years ago

Given the equation

astra-53 [7]

Answer:

1.81 x $10^{24}$ molecules H2

Explanation:

Use Avogadro's number:

3 moles H2 x 6.022 x $10^{23}$ molecules= 1.81 x $10^{24}$ molecules H2

4 0

2 years ago

A foil boat measures 4.0cm by 5.0cm and has a mass of 100.0g. If you put the boat in water, how far will it sink? (Recall the de

xxMikexx [17]

Answer:

Let the volume of the block of wood be

V

c

m

3

and its density be

d

w

g

c

m

−

3

So the weight of the block

=

V

d

w

g

dyne, where g is the acceleration due to gravity

=

980

c

m

s

−

2

The block floats in liquid of density

0.8

g

c

m

−

3

with

1

4

t

h

of its volume submerged.So the upward buoyant force acting on the block is the weight of displaced liquid

=

1

4

V

×

0.8

×

g

dyne.

Hence by cindition of floatation

V

×

d

w

×

g

=

1

4

×

V

×

0.8

×

g

⇒

d

w

=

0.2

g

c

m

-3

,

Now let the density of oil be

d

o

g

c

m

-3

The block floats in oil with 60% of its volume submerged.So the buoyant force balancing the weight of the block is the weight of displaced oil =

60

%

×

V

×

d

o

×

g

dyne

Now applying the condition of floatation we get

60

%

×

V

×

d

o

×

g

=

V

×

d

w

×

g

⇒

60

100

×

V

×

d

o

×

g

=

V

×

0.2

×

g

⇒

d

o

=

0.2

×

10

6

=

1

3

=

0.33

g

c

m

−

3

Explanation:

5 0

2 years ago

What would scientist’s next steps be if his/her data supported his/her hypothesis?

Lady bird [3.3K]

To communicate the results in an organized report

6 0

4 years ago

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