Answer:
We need 0.375 mol of CH3OH to prepare the solution
Explanation:
For the problem they give us the following data:
Solution concentration 0,75 M
Mass of Solvent is 0,5Kg
knowing that the density of water is 1g / mL, we find the volume of water:
Now, find moles of 
are needed using the molarity equation:
therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH, resulting in a concentration of 0,75M
Well, all of this we owe it to Bohr who analyzed the atomic emission spectrum of hydrogen and he could probe matematically that it was a result of movement of e- from an especific energy level to a lower one. The understanding of levels of energy took to the development of the atomic theory
V₁ = 420 mL
T₁ = 210 K
V₂ = ?
T₂ = 250 K
(Answer is 500 mL)
Answer:
0.7644 moles of H₂O
Explanation:
The balance chemical equation is as follow;
2 H₂O₂ → 2 H₂O + O₂
To solve this problem we will first calculate the moles of H₂O₂ as,
Moles = Mass / M/Mass
Moles = 26.0 g / 34.01 g/mol
Moles = 0.7644 mol
Secondly,
According to equation,
2 moles of H₂O₂ produces = 2 moles of H₂O
Hence,
0.7644 mol of H₂O₂ will produce = X moles of H₂O
Solving for X,
X = 2 mol × 0.7644 mol / 2 mol
X = 0.7644 moles of H₂O
The
balanced reaction would be written as:
<span>
C7H6O3 + C4H6O3--->C9H8O4 + HC2H3O2
To determine the percent yield, we need to first
determine the theoretical yield if the reaction were to proceed completely.
Then, we divide the actual yield that is given to the theoretical yield times
100 percent. The limiting reactant from the reaction would be salicylic acid.
We do as follows:
<span>Theoretical yield: 50.05 g C7H6O3 ( 1 mol /
138.21 g ) ( 1 mol C9H8O4 / 1 mol C7H6O3 ) ( 180.157 g / mol ) = 65.24 g C9H8O4 should be produced
Percent yield = 55.45 / 65.24 x 100 = 84.99%
<span>
Therefore, the percent yield for the given amount of salicylic acid is 84.99%
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