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3 years ago

Which events represents a chemical change ?

Chemistry

2 answers:

8_murik_8 [283]3 years ago

5 0

D milk turning sour
the other options are physical changes

yawa3891 [41]3 years ago

3 0

Hihi!

The answer would be D. milk turning sour! What happens when milk goes sour is it ferment lactose at room temperature and which turns it into lactic acid. More acid means more hydrogen ions, a lower pH and a sour taste. Lower pH change the structure of proteins like casein, which gives milk its whiteness, so it curdles into clumps called curds! It's pretty gross!

I hope I helped!
-Jailbaitasmr

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How many atoms are in 25.0 moles of calcium (Ca)?

arsen [322]

Answer:

1.8066e+24 is the answer

3 0

3 years ago

Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p

UNO [17]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

$\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M$

Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

Concentration of $Br$ = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

7 0

3 years ago

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Answer:

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= 44KJ

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= 1.498kJ + 44.0kJ

= 45.498KJ

Explanation: The heat flow can be separated into steps.all that is being observed at a constant pressure,the heat flow is equal to the enthalpy.

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3 years ago

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Anastaziya [24]

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