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3 years ago

Use the periodic table to select which type of bond is present and which of the listed properties is most

Chemistry

1 answer:

Kazeer [188]3 years ago

3 0

Answer:

A= Metallic

B= Conducts electricity as a solid

C= Covalent

D=Does not conduct electricity

Explanation:

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Which two particles each have a mass approximately equal to one atomic mass unit?

natali 33 [55]

Answer is: (4) proton and neutron.

One unified atomic mass unit is approximately the mass of one nucleon (proton or neutron).

The unified atomic mass unit (amu) is a standard unit of atom mass.

One unified atomic mass unit is approximately the mass of one nucleon (1.66·10⁻²⁷ kg).

For example, one carbon atom has mass of 12 amu (unified atomic mass).

The electron has a mass that is approximately 1/1836 that of the proton.

3 0

4 years ago

Read 2 more answers

IF your good at CHEMISTRY plls helpp!!!

gulaghasi [49]

molar concentration of Sn²⁺ ions = 0.273 M

molar concentration of Al³⁺ ions = 0.415 M

molar concentration of Cl⁻ ions = 1.692 M

Explanation:

First we calculate the number of moles of tin (II) chloride (SnCl₂) in the first solution:

number of moles = molar concentration × volume (L)

number of moles of SnCl₂ = 0.55 × 0.45 = 0.248 moles

And the number of moles of aluminum chloride (AlCl₃) in the second solution:

number of moles = molar concentration × volume (L)

number of moles of AlCl₃ = 0.7 × 0.65 = 0.455 moles

0.248 moles of SnCl₂ contains 0.248 moles of Sn²⁺ ions and 2 × 0.248 = 0.496 moles of Cl⁻ ions

0.455 moles of AlCl₃ contains 0.455 moles of Al³⁺ ions and 3 × 0.455 = 1.365 moles of Cl⁻ ions

Volume of the final solution = 450 mL + 650 mL = 1100 mL = 1.1 L

molar concentration = number of moles / volume (L)

molar concentration of Sn²⁺ ions = 0.248 / 1.1 = 0.273 M

molar concentration of Al³⁺ ions = 0.455 / 1.1 = 0.415 M

molar concentration of Cl⁻ ions = (0.496 + 1.365) / 1.1 = 1.692 M

Learn more about:

molar concentration

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6 0

4 years ago

Give a sketch illustrating the different types of interconversion

nadya68 [22]

Answer:

there you go

Explanation:

6 0

3 years ago

An intravenous infusion is to contain 15 mEq of potassium ion and 20 mEq of sodium ion in 500 mL of 5% dextrose injection. Using

Studentka2010 [4]

Answer:

To supply the required ions it is necessary to inject 5,6mL of 6g/30mL solution and 131,1 mL of 0,9% solution.

Explanation:

1mEq of sodium are 59mg of NaCl and 1mEq of potassium are 75mg KCl

in intravenous infusion 15 mEq of K are:

15x75mg KCl = 1,125g of KCl

And 20 mEq of Na are:

20x59mg NaCl = 1,18g of NaCl

To supply the potassium ion it is necessary to inject:

1,125g of KCl× $\frac{30mL}{6g}$ = 5,6mL of 6g/30mL solution

And, to supply the sodium ion it is necessary to inject:

1,18g of NaCl× $\frac{100mL}{0,9g}$ = 131,1 mL of 0,9% solution

I hope it helps!

6 0

4 years ago

The limiting reactant, O2, can form up to 2.7 mol Al2O3. What mass of Al2O3 forms?

Margaret [11]

Answer:

280 g Al₂O₃

Explanation:

To find the mass, you need to multiply the given value by the molar mass. This will cause the conversion because the molar mass exists as a ratio; technically, the ratio states that there are 101.96 grams per every 1 mole Al₂O₃. It is important to arrange the ratio in a way that allows for the cancellation of units. In this case, the desired unit (grams) should be in the numerator. The final answer should have 2 sig figs to reflect the given value (2.7 mol).

Molar Mass (Al₂O₃): 101.96 g/mol

2.7 moles Al₂O₃ 101.96 g
------------------------ x ------------------- = 275 g Al₂O₃ = 280 g Al₂O₃
1 mole

5 0

2 years ago