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Nina [5.8K]
3 years ago
10

Albert dressed as TWO-FACE flips a coin up in the air at an upward velocity of 5.00 m/s. He fails to catch it on the way down an

d it falls down an 8.5 m deep well. Calculate the maximum height and maximum magnitude (could be positive or negative) of velocity of the coin.
Physics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

1.28 m, 14 m/s

Explanation:

At the maximum height, the velocity is 0.

Given:

a = -9.8 m/s²

v₀ = 5.00 m/s

v = 0 m/s

x₀ = 0 m

Find:

x

v² = v₀² + 2a(x - x₀)

(0 m/s)² = (5.00 m/s)² + 2(-9.8 m/s²) (x - 0 m)

x = 1.28 m

The maximum speed is at the bottom of the well.

Given:

a = -9.8 m/s²

v₀ = 5.00 m/s

x₀ = 0 m

x = -8.5 m

Find:

v

v² = v₀² + 2a(x - x₀)

v² = (5.00 m/s)² + 2(-9.8 m/s²) (-8.5 m - 0 m)

v = -13.8 m/s

Rounded to 2 sig-figs, the maximum speed is 14 m/s.

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Explanation:

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6 0
3 years ago
A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


5 0
3 years ago
a ball of mass 0.5 kg moving at 10 m/s collides with another ball of equal mass at rest. if the two balls move off together afte
nexus9112 [7]

Answer:

5 m/s

Explanation:

Here we can see there is no external force acted on a two masses when we consider the motion. If there is no external forces then momentum is conserved.

Initial momentum = Final momentum

0.5 × 10  = 1 × V

V = 5 m/s

7 0
3 years ago
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