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Nina [5.8K]
3 years ago
10

Albert dressed as TWO-FACE flips a coin up in the air at an upward velocity of 5.00 m/s. He fails to catch it on the way down an

d it falls down an 8.5 m deep well. Calculate the maximum height and maximum magnitude (could be positive or negative) of velocity of the coin.
Physics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

1.28 m, 14 m/s

Explanation:

At the maximum height, the velocity is 0.

Given:

a = -9.8 m/s²

v₀ = 5.00 m/s

v = 0 m/s

x₀ = 0 m

Find:

x

v² = v₀² + 2a(x - x₀)

(0 m/s)² = (5.00 m/s)² + 2(-9.8 m/s²) (x - 0 m)

x = 1.28 m

The maximum speed is at the bottom of the well.

Given:

a = -9.8 m/s²

v₀ = 5.00 m/s

x₀ = 0 m

x = -8.5 m

Find:

v

v² = v₀² + 2a(x - x₀)

v² = (5.00 m/s)² + 2(-9.8 m/s²) (-8.5 m - 0 m)

v = -13.8 m/s

Rounded to 2 sig-figs, the maximum speed is 14 m/s.

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Sound travels about 750 miles per hour. if you stand in a canyon and sound a horn, you will hear an echo. suppose it takes about
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A 2000 kg car slams on the brakes and slows down at a rate of -10 m/s2. How much force are the brakes applying?
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Answer:

-20,000N

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5 0
3 years ago
a particle is moving along a circular path having a radius of 4 in such that its position as a function of time is given by thet
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Answer:

Explanation:

Given

radius of circular path r=4\ in.

Position is given by

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Differentiate 1  to angular velocity we get

\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega =-2\sin 2t----2

Differentiate 2 to get angular acceleration

\frac{\mathrm{d} \omega }{\mathrm{d} t}=-2^2\cos 2t ---3

Net acceleration is the vector summation of tangential and centripetal force

a_t=\alpha \times r

a_t=-4\cos 2t\times 4=-16\cos 2t

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a_r=16\sin^2(2t)

a_{net}=\sqrt{a_r^2+a_t^2}

a_{net}=\sqrt{(16\sin ^2(2t)+(-16\cos 2t)^2}

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Explanation:

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As such:

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Mathematically, it can be computed as:

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\mathbf{v_{avg} =12.31 \ m/s}

8 0
3 years ago
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