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BigorU [14]
3 years ago
14

A TV draws 0.867 A of current when connected to a 122 V outlet. It’s resistance is 140.71.

Physics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

Explanation:

current measures charge flowing per second .

A current of .867 A means charge of .867 coulomb is flowing per second

charge flowing per minute = .867 x 60

= 52.02 coulomb

one electrons carries a charge of 1.6 x 10⁻¹⁹ Coulomb

So no of charge flowing per minute

= 52.02 / 1.6 x 10⁻¹⁹

= 32.5 x 10¹⁹ .

B )

electrical energy consumed per minute

= V X I X t , V is volt , I is current and t is time .

= 122 x .867 x 60

= 6346.44 J .

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Now, by momentum conservation and energy conservation:

   mv = mv_{m} + Mv_{M}

   mv^{2} = mv^{2}_{m} + Mv^{2}_{M}

Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.

   v_{m} = v\frac{m - M}{m + M}\\\\\\v_{M} = v\frac{m + M}{m + M}\\

So now, we see that v_{m} < 0 and v_{M} > 0. So therefore, the smaller mass recoils out.

Hope this helps you!

Bye!

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3 years ago
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3 years ago
If a an object is traveling at a rate of 5 meters per second squared with a force of 10 Newtons, what is the mass of the object?
Svetllana [295]

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2 kg

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Acceleration = 5 m/s^2

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8 0
2 years ago
How does light and heat energy from the sun reach earth?
defon

Explanation:

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6 0
2 years ago
Okay i'm totally stuck and nobody I know really gets it either, so i've turned to Yahoo for help :)
OlgaM077 [116]

Here is the rule for see-saws here on Earth, and there is no reason
to expect that it doesn't work exactly the same anywhere else:

                     (weight) x (distance from the pivot) <u>on one side</u>
is equal to
                     (weight) x (distance from the pivot) <u>on the other side</u>.

That's why, when Dad and Tiny Tommy get on the see-saw, Dad sits
closer to the pivot and Tiny Tommy sits farther away from it.

       (Dad's weight) x (short length) = (Tiny Tommy's weight) x (longer length).


So now we come to the strange beings on the alien planet.
There are three choices right away that both work:

<u>#1).</u>
(400 N) in the middle-seat, facing (200 N) in the end-seat.

       (400) x (1)  =    (200) x (2)

<u>#2).</u>
(200 N) in the middle-seat, facing (100 N) in the end-seat.

       (200) x (1)  =    (100) x (2)

<u>#3).</u>

On one side:  (300 N) in the end-seat       (300) x (2) = <u>600</u>

On the other side:
                      (400 N) in the middle-seat  (400) x (1) = 400
           and     (100 N) in the end-seat      (100) x (2) = 200
                                                    Total . . . . . . . . . . . . <u>600</u> 


These are the only ones to be identified at Harvard . . . . . . .
There may be many others but they haven't been discarvard.


5 0
3 years ago
Read 2 more answers
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