The formula is NaCi, containing equal amounts of sodium and chloride
Answer:
18.45 g of C
Explanation:
This is a problem of rules of three:
1 mol of C₃H₈ contains 3 moles of C and 8 moles of H
If 8 moles of H are contained in 1 mol of propane
4.10 moles of H are contained in (4.1 . 1) /8 = 0.5125 moles
Now, If 1 mol of propane contains 3 moles of C
0.5125 moles of propane may contain (0.5125 . 3) / 1 = 1.5375 moles of C
Let's convert the moles to mass:
1.5375 mol . 12 g /mol = 18.45 g
The elements in each group have the same number of electrons in the outer orbital<span>. Those </span>outer<span> electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements. Every element in the first column (group one) has one electron in its </span>outer<span> shell.</span>
8:24 = 0.333(3) pints is one percent
0.333(3)* 100=33.333(3) pints will be 24% mixture with the water
33.3333-8=25.333 pints of water is required for producing 24% mixture
25.3333 pints of pure water and 8 pints of juce.
Answer is: no reaction occurs.
No reaction occurs because magnesium (Mg) is less reactive than sodium (Na). Sodium is higher in activity series of metals and can not be reduced. <span> Metal X will replace another metal Y in a solution if X is higher in the activity series. </span>