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3 years ago

What is the equation adheres to the law of conservation of matter

Chemistry

1 answer:

Citrus2011 [14]3 years ago

7 0

Answer:

any equation where it starts with the same number of stuff and ends with the same number of stuff. you cna usually do this by balancing an equation

Explanation:

2Na + S = Na2S

Li + Cl = LiCl

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The Newton is the SI unit for ____. temperature density weight mass

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Answer:

Mass

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3 years ago

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To determine molecular mass

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2 years ago

All cells in living organisms undergo cellular respiration. The chemical reaction for cellular respiration is stated below. (Glu

Ne4ueva [31]

Answer : The total mass of carbon dioxide and water produced will be, 65.7 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

$C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O$

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of $C_6H_{12}O_6+6O_2$ = Total mass of $6CO_2+6H_2O$

As we are given :

Total mass of $C_6H_{12}O_6+6O_2$ = 65.7 grams

So,

65.7 grams = Total mass of $6CO_2+6H_2O$

Therefore, the total mass of carbon dioxide and water produced will be, 65.7 grams.

4 0

3 years ago

A galvanic cell with E o cell = 0.30 V can be constructed using an iron electrode in a 1.0 M Fe(NO3)2 solution, and either a tin

Andreyy89

Answer: The half reactions are written below.

Explanation:

Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

We are given a chemical cell which is Fe-Sn cell. The half reaction follows:

Oxidation half reaction: $Fe\rightarrow Fe^{2+}+2e^-;E^o_{Fe^{2+}/Fe}=-0.44V$

Reduction half reaction: $Sn^{2+}+2e^-\rightarrow Sn;E^o_{Sn^{2+}/Sn}=-0.14V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, zinc will always undergo reduction reaction will get reduced.

Total cell reaction: $Fe+Sn^{2+}\rightarrow Fe^{2+}+Sn$

Hence, the half reactions are written above.

3 0

3 years ago

Consider the reaction mg(oh)2(s)→mgo(s)+h2o(l) with enthalpy of reaction δhrxn∘=37.5kj/mol what is the enthalpy of formation of

Anni [7]

Answer is: -601,2 kJ/mol
Chemical reaction: Mg(OH)₂ → MgO + H₂O.
ΔHrxn = 37,5 kJ/mol.
ΔHf(Mg(OH)₂) = −924,5 kJ/mol.
ΔHf(H₂O) = −285,8 kJ/mol.
ΔHrxn -enthalpy of reaction.
ΔHf - enthalpy of formation.
ΔHrxn=∑productsΔHf−∑reactantsΔHf.
ΔHf(MgO) = -924,5 kJ/mol - (-285,8 kJ/mol) + 37,5 kj/mol.
ΔHf(MgO) = -601,2 kJ/mol.

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3 years ago

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