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3 years ago

What is always included in a comparative investigation?

Chemistry

2 answers:

quester [9]3 years ago

7 0

Answer:it’s is B a scientific question not hypothesis

Explanation:

Taya2010 [7]3 years ago

6 0

Answer:

the answer is scientific question

Explanation:

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Where do expect to find the most reactive metals on the periodic table;?

faltersainse [42]

The most reactive metals on the periodic table would have to be the alkali metals.
I hope this helps!
Have a nice day (:

5 0

3 years ago

Read 2 more answers

“While observing a chemical reaction, how can you tell which reactant is limiting?”

bulgar [2K]

Answer:

Then the substance would be the first to run out which signifies the completing of the reaction.

Explanation:

3 0

4 years ago

Write a complete, balanced chemical equation where tin metal reacts with aqueous hydrochloric acid to produce tin(II) chloride a

Naily [24]

Answer:

Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)

Explanation:

The net reaction is Z n ( s ) + 2 H + ( a q ) → Z n 2 + ( a q ) + H 2 ( g ) The C l − ions are spectators - they don't change.

7 0

3 years ago

The combustion of 0.590 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera

Alenkinab [10]

Answer:

2.943 °C temperature change from the combustion of the glucose has been taken place.

Explanation:

Heat released on combustion of Benzoic acid; :

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.590 g

Moles of benzoic acid = $\frac{0.590 g}{122.12 g/mol}=0.004831 mol$

Energy released by 0.004831 moles of benzoic acid on combustion:

$Q=3,228 kJ/mol \times 0.004831 mol=15.5955 kJ=15,595.5 J$

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.125°C

$Q=C\times \Delta T$

$15,595.5 J=C\times 2.125^oC$

$C=7,339.05 J/^oC$

Heat released on combustion of Glucose: :

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=1.400 g

Moles of glucose = $\frac{1.400 g}{180.16 g/mol}=0.007771 mol$

Energy released by the 0.007771 moles of calorimeter combustion:

$Q'=2,780 kJ/mol \times 0.007771 mol=21.6030 kJ=21,603.01 J$

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

$Q'=C\times \Delta T'$

$21,603.01 J=7,339.05 J/^oC\times \Delta T'$

$\Delta T'=2.943^oC$

2.943 °C temperature change from the combustion of the glucose has been taken place.

8 0

3 years ago

Which of the following is the correct measurement for the volume of liquid shown below?

mr Goodwill [35]

Answer:

A. 3.5ml

Explanation:

lowest point of liquid or meniscus

5 0

3 years ago