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mixas84 [53]
3 years ago
13

X=3t^2-12t+5 calculate time t=1 and time when velocity zero

Physics
1 answer:
anyanavicka [17]3 years ago
4 0
You plug your 1 into all spots where the variable is T. Then after you’ve done this, you simply simplify the problem. Then after simplifying you should have an equation where you are simply adding and subtracting which will give you the final answer of 2.

X=3T^2-12T+5
X=3(1)^2-12(1)+5
X=(3)^2-12+5
X=9-12+5

X=2
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A wooden block is sitting on an inclined plane near the bottom. The student gave the block a flick and it moved up the inclined
sladkih [1.3K]

Answer:

The block didn't slide due to balancing of gravitational force with friction force

Explanation:

When the block was given a flick the force provided an acceleration to it and it moved up the inclined plane. when the block reached top it was expected that it would slide back but it didn't this happened because of the frictional force acting on the bottom the block which was balancing the gravitational force component along the plane and this prevented sliding back of the block.

static friction  was balancing mg*sin(theta)

fs = mg*sin(theta)

6 0
3 years ago
Calculate the mass (in g) of 346 cm³ of polythene. The density of polythene is 0.95 g/cm³. Give your answer to 2 decimal places.
IceJOKER [234]

Answer:

M = 328.70g

Explanation:

From the given values:

V = 346 cm³

M of 1 cm³ of Polythene = 0.95g or 95/100g

Solve:

M = <u>(95×346)</u>

10

= <u>3</u><u>2</u><u>8</u><u>7</u><u>0</u>

100

M = 328.70g

8 0
2 years ago
What will happen if a car experiences a 300 N force to the right from the engine and a separate 150 N force due to friction and
gayaneshka [121]

Force applied on the car due to engine is given as

F_1 = 300 N towards right

Also there is a force on the car towards left due to air drag

F_2 = 150 N towards left

now the net force on the car will be given as

\vec F_{net} = \vec F_1 + \vec F_2

now we can say that since the two forces are here opposite in direction so here the vector sum of two forces will be the algebraic difference of the two forces.

So we can say

F_{net} = F_1 - F_2

F_{net} = 300 - 150

F_[net} = 150 N

So here net force on the car will be 150 N towards right and hence it will accelerate due to same force.

5 0
3 years ago
What current flows through a 2.54cm diameter rod of pure silicon that is 20cm long when 1000V is applied?
vfiekz [6]

Answer: 0.0039\ A

Explanation:

Given

Diameter of the rod d=2.54\ cm

length of rod is l=20\ cm

Resistivity of silicon is \rho=6.4\times 10^2\ \Omega-m

cross-section of the rod A

\Rightarrow A=\dfrac{\pi d^2}{4}\\\\\Rightarrow A=\dfrac{3.142\times 2.54^2\times 10^{-4}}{4}\\\\\Rightarrow A=5.067\times 10^{-4}\ m^2

Resistance of rod is  R

\Rightarrow R=\dfrac{\rho l}{A}

\Rightarrow R=\dfrac{640\times 0.20}{5.067\times 10^{-4}}\\\\\Rightarrow R=25.26\times 10^4\ \Omega

Current is given by

\Rightarrow I=\dfrac{V}{R}\\\\\Rightarrow I=\dfrac{1000}{25.26\times 10^4}\\\\\Rightarrow I=0.0039\ A

3 0
2 years ago
1. A stationary 50 tonne submarine fires a missile of mass 40kg at
White raven [17]

The velocity of the submarine immediately after firing the missile is 0.0104 m/s

Explanation:

Mass of the submarine M=50 tonne=50\times 1000=50000kg

Mass of the missile m=40  kg

velocity of the missile v= 13m/s

we have to calculate the velocity of the submarine after firing

This is the recoil velocity and its expression is derived from the law of conservation of momentum

recoil velocity of the submarine

V=-mv/M\\=-40\times 13/50000\\=0.0104 m/s

8 0
3 years ago
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