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Olegator [25]
2 years ago
7

Why did Hubble's data change our view of the universe?

Physics
1 answer:
olasank [31]2 years ago
7 0

Answer:

Hubble has helped survey galaxies that existed when the universe was only 600 million years old. Previous estimates had suggested that galaxies didn't form until the universe was at least two billion years old. The instrument's images have helped scientists understand how galaxies evolve.

Explanation:

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Which method is used to separate parts of a solution when the entire solution can pass through a filter?
creativ13 [48]

Answer:

Straining method

Explanation:

Straining method is the method that can be used to separate parts of a liquid mixture when the entire mixture can pass through a filter.

3 0
3 years ago
Please help- it’s a 15 point change to my grade.
Harman [31]

Answer: Everything except heat and density

Explanation:

6 0
2 years ago
Question one please! This is 8th grade science btw.
yKpoI14uk [10]

Good Luck, NYAYAYAYAYa

8 0
3 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen
bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

f_{a} =(\frac{v+v_{c} }{v} )f_{s} (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s} (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s

b) Substitute eq. 1 in eq. 2:

f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz

7 0
3 years ago
Charging a balloon by rubbing it on wool is an example of
SVETLANKA909090 [29]
Electronic friction ^.^
3 0
3 years ago
Read 2 more answers
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