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Olegator [25]
3 years ago
7

Why did Hubble's data change our view of the universe?

Physics
1 answer:
olasank [31]3 years ago
7 0

Answer:

Hubble has helped survey galaxies that existed when the universe was only 600 million years old. Previous estimates had suggested that galaxies didn't form until the universe was at least two billion years old. The instrument's images have helped scientists understand how galaxies evolve.

Explanation:

You might be interested in
Assume that the surface temperature of the lightbulb filament when it is plugged into an outlet of 120 V is about 3000 K and the
myrzilka [38]

Answer:

A=8.7\times 10^{-7}m^{2}

Explanation:

We have given power =40 W but only 10% of this power is used so actual power P=\frac{40\times 10}{100}=4 W

We know that from Stefan's law p=\sigma AT^4 where \sigma is Boltzmann constant which value is 5.6\times 10^{-8}Wm^{-2}K^{-4}

So 4=5.67\times 10^{-8}\times A\times 3000^4

A=8.7\times 10^{-7}m^{2}

4 0
3 years ago
Read 2 more answers
Charlie pulls horizontally to the right on a wagon with a force of 37.2 N. Sara pulls horizontally to the left with a force of 2
Sidana [21]

Answer:

The work done on the wagon is 37 joules.

Explanation:

Given that,

The force applied by Charlie to the right, F = 37.2 N

The force applied by Sara to the left, F' = 22.4 N

We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :

F_n=F-F'

F_n=37.2-22.4

F_n=14.8\ N

Work done on the wagon is given by the product of net force and displacement. It is given by :

W=F_n\times d

W=14.8\ N\times 2.5\ m

W = 37 Joules

So, the work done on the wagon is 37 joules. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
Calculate the equivalent of 20 degrees Celsius in degrees Fahrenheit and Kelvin.
alekssr [168]

Answer:

68 °F, 293.15 K

Explanation:

Fahrenheit, Kelvin and Celsius are the different scales of temperature in which temperature is measured.

Given : T = 20°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

<u>T = (20 + 273.15) K = 293.15 K </u>

The conversion of T( °C) to T(F) is shown below:

T (°F) = (T (°C) × 9/5) + 32

So,

<u>T (°F) = (20 × 9/5) + 32 = 68 °F</u>

3 0
3 years ago
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22
alexgriva [62]
1) The law of motion of the projectile is
h(t) = 2+22.5 t-4.9 t^2
To find the velocity, we should compute the derivative of h(t):
v(t)=h'(t)=22.5-2\cdot 4.9t=22.5-9.8t
So now we can calculate the speed at t=2 s and t=4 s:
v(2.0s)=22.5-9.8\cdot2.0 =2.9 m/s
v(4.0s)=22.5-9.8\cdot 4.0s=-16.7 m/s
The negative sign in the second speed means the projectile has already reached its maximum height and it is now going downward.

2) The projectile reaches its maximum height when the speed is equal to zero:
v(t)=0
So we have
22.5-9.8 t=0
And solving this we find
t=2.30 s

3) To find the maximum height, we take h(t) and we just replace t with the time at which the projectile reaches the maximum height, i.e. t=2.30 s:
h(2.30 s)=2+22.5\cdot 2.30 -4.9 \cdot (2.30s)^2 = 27.83 m

4) The time at which the projectile hits the ground is the time at which the height is zero: h(t)=0. So, this translates into
2+22.5t -4.9 t^2 = 0
This is a second-order equation, and if we solve it we get two solutions: the first solution is negative, so we can ignore it since it's physically meaningless; the second solution is
t=4.68 s
And this is the time at which the projectile hits the ground.

5) The velocity of the projectile when it hits the ground is the velocity at time t=4.68 s:
v(4.68 s)=22.5-9.8\cdot 4.68 =-23.36  m/s
with negative sign, because it is directed downward.
8 0
4 years ago
What is the magnitude of the force a charge 25uc exerts on a charge 3mc 35 cm away?
Misha Larkins [42]
5.51 × 10 power 12 newton is answer
3 0
3 years ago
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