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Tems11 [23]
2 years ago
11

The decomposition of carbon disulfide to carbon monosulfide and sulfur is first order with k=2.8 ×10^-7 at 1000°C .What is the h

alf-life of this reaction at 1000°C?
Chemistry
1 answer:
RoseWind [281]2 years ago
6 0

Answer:

2.5×10⁶ s

Explanation:

From the question given above, the following data were obtained:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

The half-life of a first order reaction is given by:

Half-life (t½) = 0.693 / Rate constant (K)

t½ = 0.693 / K

With the above formula, we can obtain the half-life of the reaction as follow:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

t½ = 0.693 / K

t½ = 0.693 / 2.8×10¯⁷

t½ = 2.5×10⁶ s

Therefore, the half-life of the reaction is 2.5×10⁶ s

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Ba(OH)_2\rightarrow \bold{\green{Barium\: hydroxide}}

Ca(OH)_2\rightarrow \bold{\red{Calcium\: hydroxide}}

RbOH \rightarrow \bold{\blue{Rubidium \:hydroxide}}

3 0
2 years ago
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In what way are electrons quantized?
KiRa [710]

<u>Answer:</u> The correct option is A) They have fixed energy values.

<u>Explanation:</u>

Electron is one of the sub-atomic particle present around the nucleus of an atom which is negatively charged.

In an atomic model, it is assumed that the electron revolves around the nucleus in discrete orbits having fixed energy levels.

These electrons when jumping from one energy level to another, some amount of radiation is either emitted or absorbed.

These fixed energy levels are given by the Bohr model and thus, the electrons are quantized.

Hence, the correct option is A) They have fixed energy values.

6 0
3 years ago
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What is the symbol of the ion with 36 electrons and a +2 charge?
AlladinOne [14]

Answer:

Strontium

Explanation:

The atomic number of strontium is 38.

It has 38 electrons.

It is alkaline earth metal. It has two valance electrons.

Strontium loses its two electrons and form cation with +2 charge.

Electronic configuration;

Sr₃₈ = [Kr] 5s²

The valance electrons present in 5s are lost by strontium atom and form Sr⁺² cation.

it is yellowish-white metal.

It is highly reactive.

It form salt with halogens.e.g

Sr    +   Br₂    →     SrBr₂

IT react with oxygen and form oxide.

2Sr   +   O₂   →    2SrO

this oxide form hydroxide when react with water,

SrO  + H₂O   →  Sr(OH)₂

With nitrogen it produced nitride,

3Sr + N₂     →  Sr₃N₂

With acid like HCl,

Sr + 2HCl  →  SrCl₂ + H₂

3 0
3 years ago
Which of the halide ions (f−, cl−, br−, and i−) is the most stable base? which is the least stable base?
Nezavi [6.7K]
You should take note that the question is about stability. A compound is stable if it does not easily react with other elements. Hence, its reactivity must be low. As you move down the group, reactivity decreases. So, the halide at the very bottom is the least reactive. It would then be logical that the most stable conjugate base is I⁻ and the least stable conjugate base is the most reactive which is F⁻.
3 0
2 years ago
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A solution is prepared by adding 0.0231moles of H3O+ ions to 3.33L of water. What is the pH of this solution
MrMuchimi

Answer:

2.15

Explanation:

For this question, we have to remember the <u>pH formula</u>:

pH~=~-Log[H_3O^+]

By definition, the pH value is calculated when we do the -Log of the concentration of the <u>hydronium ions</u> (H_3O^+). So, the next step is the calculation of the <u>concentration</u> of the hydronium ions. For this, we have to use the <u>molarity formula</u>:

M=\frac{mol}{L}

We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:

M=\frac{0.0231~moles}{3.33~L}=0.00693~M

With this value, now we can calculate the pH value:

pH~=~-Log[0.00693~M]~=~2.15

<u>The pH would be 2.15</u>

I hope it helps!

8 0
2 years ago
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