Answer:
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<u>Given:</u>
Concentration of NaClO = 0.037 M
ka (HClO) = 4.0*10⁻⁸
<u>To determine:</u>
The pH of the NaClO solution
<u>Explanation:</u>
The hydrolysis of the weak base can be represented by the ICE table shown below-
ClO- + H2O ↔ HClO + OH-
Initial 0.037M 0 0
Change -x +x +x
Equilibrium (0.037-x) x x
kb = kw/ka = [HClO][OH-]/[ClO-]
10⁻¹⁴/4*10⁻⁸ = x²/(0.037-x)
x = [OH-] = 9.62*10⁻⁵
p[OH-] = -log[OH-] = -log [9.62*10⁻⁵] = 4.02
pH = 14-p[OH-] = 14 - 4.02 = 9.98
Ans: pH of the solution is 9.98
Answer:
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