Answer:
Mass % of hydrogen = 20.9 %
Explanation:
Given data:
Mass of hydrogen = 0.485 g
Mass of water = 2.32 g
Mass percent of hydrogen = ?
Solution:
Mass % of hydrogen = mass of hydrogen / mass of water × 100
Mass % of hydrogen = 0.485 g/ 2.32 g × 100
Mass % of hydrogen = 0.209 × 100
Mass % of hydrogen = 20.9 %
At STP (standard temperature and pressure conditions), 1 mol of any gas occupies 22.4 L
This rule is applied to O₂
22.4 L volume occupied by 1 mol
Therefore 83.4 L occupied by - 1/ 22.4 x 83.4 = 3.72 mol
stoichiometry of O₂ to H₂O is 1:2
then the number of moles of water produced - 3.72 mol x 2= 7.44 mol
mass of water produced - 7.44 mol x 18.01 g/mol = 134.1 g
correct answer is D
Question:
Each liter of air has a mass of 1.80 grams. How many liters of air are contained in 2.5 x103) kg of air?
Answer:
11.48106 L
