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Sergeu [11.5K]
2 years ago
9

how many electrons is Fluorine likely to receive from the atom of another element during the formation of a bond.

Chemistry
1 answer:
S_A_V [24]2 years ago
8 0

Answer: Fluorine contains seven valence electrons. It needs one more electron to complete its octet. The oxidation number is 1- and indicates fluorine will gain or share one electron when it combines with another atom to become a more stable compound.

Explanation: Fluorine contains seven valence electrons. It needs one more electron to complete its octet. The oxidation number is 1- and indicates fluorine will gain or share one electron when it combines with another atom to become a more stable compound.

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Reaction with lithium and aluminum chloride formula?
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Which is a factor in determining the average atomic mass of an element?
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The factor in determining the average atomic mass of an element is: 
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his is the chemical formula for epinephrine (the main ingredient in adrenaline): C9H13O3N A biochemist has determined by measure
Len [333]

Answer:

3.67 moles of N

Explanation:

The epinephrine's chemical formula is: C₉H₁₃O₃N

We were told that a chemist found that in a mesaure of epinephrine, he found 33 moles of C

We must know that 9 moles of C are in 1 mol of C₉H₁₃O₃N so, let's make a rule of three:

If 9 moles of C are found in 1 mol of C₉H₁₃O₃N

Therefore 33 moles of C must be found in (33 .1) / 9 = 3.67 moles of C₉H₁₃O₃N

There is a second rule of three, then.

In 1 mol of C₉H₁₃O₃N we have 1 mol of N

Then, 3.67 moles C₉H₁₃O₃N must have (3.67 . 1) / 1 = 3.67 moles of N

Remember 1 mol of C₉H₁₃O₃N has 9 moles of C, 13 moles of H, 3 moles of O and 1 mol of N

5 0
3 years ago
Find the ph of a buffer that consists of 0.18 m ch3nh2 and 0.73 m ch3nh3cl (pkb of ch3nh2 = 3.35)?
ozzi
Hello!

First, we need to determine the pKa of the base. It can be found applying the following equation:

pKa=14-pKb=14-3,35=10,65

Now, we can apply the Henderson-Hasselbach's equation in the following way:

pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04

So, the pH of this buffer solution is 10,04

Have a nice day!
8 0
2 years ago
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