Answer:
Explanation:
Hello,
In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:
Clearly, the concentrated solution is 12M and the diluted solution is 0.5 M, thus, the volume of the concentrated solution we should take is:
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Answer:
5x10⁻⁶ = [HTeH₄O₆⁺]
Explanation:
The first dissociation equilibrium of the telluric acid in water is:
H₂TeH₄O₆ + H₂O ⇄ HTeH₄O₆⁺ + H₃O⁺
Using H-H equation for telluric acid:
<em>pH = pKa + log₁₀ [HTeH₄O₆⁺] / [H₂TeH₄O₆]</em>
pKa of telluric acid is -logKa1
pKa = -log 2.0x10⁻⁸
pKa = 7.699
As concentration of [H₂TeH₄O₆] is 0.25M, replacing in H-H equation:
3.00 = 7.699+ log₁₀ [HTeH₄O₆⁺] / [0.25M]
-4.699 = log₁₀ [HTeH₄O₆⁺] / [0.25M]
2x10⁻⁵ = [HTeH₄O₆⁺] / [0.25M]
<h3>5x10⁻⁶ = [HTeH₄O₆⁺]</h3>
Answer:
See Explanation
Explanation:
Note => 1st one should understand that for an 'acid' to be an acid and a 'base' to be a base, two requirements must be met, (1) the compound must have an ionizable Hydrogen for acids or Hydroxide for bases, and (2) must be in water and ionize delivering H⁺ ions from acids and OH⁻ ions from bases. The Arrhenius acids are characterized by having an ionizable hydrogen which when added into water increases the hydronium ion concentration (H₃O⁺). Arrhenius bases are characterized by having an ionizable hydroxide function (OH-).
Typically, the acids and bases are characterized as either strong or weak electrolytes. the Strong electrolytes ionize 100% in water and Weak electrolytes less than 100%.
The strong acids include HCl, HBr, HI, HNO₃, HClO₄ and H₂SO₄ (1st ionization step). Any acid (H-Anion) not a member of the strong 6 is a weak acid.
The strong Arrhenius Bases are Group IA and Group IIA Hydroxides except for Beryllium Hydroxide. Weak Arrhenius Bases are ammonia or ammonia derivatives (amines) in water.
=> NH₃ + H₂O => NH₄OH ⇄ NH⁺ + OH⁻.
The ammonia derivatives follow the same reactive nature in water.
=> RNH₂ + H₂O => RNH₃OH ⇄ RNH₃⁺ + OH⁻ where R- is a structural substrate; e.g., Methyl Amine => H₃C - NH₂ .
I am not sure, but I think that “It will not change.”
