All categories

3 years ago

Name four products of incomplete combustion One : Two : Three : Four :

Chemistry

1 answer:

melamori03 [73]3 years ago

8 0

Answer:

Carbon Monoxide / Carbon Dioxide / Sulfur and Nitrogen Dioxide

Explanation:

You might be interested in

When the burner in a hot air balloon is turned on, the temperature of the air in the balloon ________ causing its volume to ____

raketka [301]

B) increases, expand, rises

4 0

3 years ago

What kind of compound has two atoms in it

statuscvo [17]

H20 can be a molecule or a compound because it is made up of Hydrogen(H)

and oxygen (O)

7 0

3 years ago

A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is us

Zinaida [17]

Answer:

A. 96.3 mg/dL

Absolute error: 5.7 mg/dL

Relative error: 5.6%

B. 97.2 mg/dL

Absolute error: 4.8 mg/dL

Relative error: 4.7%

C. 104.8 mg/dL

Absolute error: 2.8 mg/dL

Relative error: 2.7%

D. 111.5 mg/dL

Absolute error: 9.5 mg/dL

Relative error: 9.3%

E. 110.5 mg/dL

Absolute error: 8.5 mg/dL

Relative error: 8.3%

Explanation:

The formula for the absolute error is:

Absolute error = |Actual Value - Measured Value|

The formula for the relative error is:

Relative error = |Absolute error/Actual value|

In your exercise, we have that

Actual Value = 102.0 mg/dL

A. 96.3 mg/dL:

$E_{ABS} = |102.0 - 96.3| = 5.7mg/dL$

$E_{R} = \frac{5.7}{102} = 0.056 = 5.6%$

B. 97.2 mg/dL

$E_{ABS} = |102.0 - 97.2| = 4.8mg/dL$

$E_{R} = \frac{4.8}{102} = 0.047 = 4.7%$

C. 104.8 mg/dL

$E_{ABS} = |102.0 - 104.8| = 2.8mg/dL$

$E_{R} = \frac{2.8}{102} = 0.027 = 2.7%$

D. 111.5 mg/dL

$E_{ABS} = |102.0 - 111.5| = 9.5mg/dL$

$E_{R} = \frac{9.5}{102} = 0.093 = 9.3%$

E. 110.5 mg/dL

$E_{ABS} = |102.0 - 111.5| = 8.5mg/dL$

$E_{R} = \frac{8.5}{102} = 0.083 = 8.3%$

4 0

3 years ago

How many moles of helium gas are contained in a 4.0 L flask at STP

Ratling [72]

First, you convert liters to moles.
Usually you have to go to grams but this is STP.

Get moles directly by dividing the 4 by STP (22.4)
$\frac{4}{22.4} =0.17857142857$
About $1.8*10^{-1}$ or 0.18 moles whichever your teacher prefers

3 0

3 years ago

Which ions remain in solution after pbi2 precipitation is complete? express your answers as ions separated by a comma?

olga nikolaevna [1]

Answer;

K+ and NO3- ions

Explanation;

The main ions remaining are K+ and NO3- ions after pbi2 precipitation is complete.

However; There will always be tiny amounts of Pb2+ and I- ions, but most of them are in the solid precipitate.

7 0

3 years ago