As you go down the table, more electron shells are added to make the radius larger, but as you go to the right, the protons' attraction increases so the radius actually shrinks. <span>Therefore, according to the trend, Cl has a larger radius because it is lower in the table.</span>
Answer: CL has a larger Atomic Radius.
Answer:
λ = 4.59 ×10⁻³ nm
Explanation:
Given data:
Energy of light = 4.33 ×10⁻¹⁴ J
Wavelength of light = ?
h = 6.626×10⁻³⁴ js
c = 3×10⁸ m/s
Solution:
Formula:
E = hc/λ
4.33 ×10⁻¹⁴ J = 6.626×10⁻³⁴ Js× 3×10⁸ m/s / λ
λ = 6.626×10⁻³⁴ Js× 3×10⁸ m/s / 4.33 ×10⁻¹⁴ J
λ = 19.878 ×10⁻²⁶ Jm / 4.33 ×10⁻¹⁴ J
λ = 4.59 ×10⁻¹² m
λ = 4.59 ×10⁻³ nm
Homogeneous because it is unable to be distinguished of the components Water and Salt
The empirical formula of the metal oxide would be 
<h3>What is empirical formula?</h3>
Mass of scandium = 0.502g
Mass of scandium + oxygen = 0.768g
Mass of oxygen = 0.768 - 0.502 = 0.266g
Mole of scandium = 0.502/44.95 = 0.011
Mole of oxygen = 0.266/16 = 0.017
Divide by the lowest:
Scandium = 0.011/0.011 = 1
Oxygen = 0.017.0.011 = 1.5
Thus, the empirical formula of the compound would be 
or
More on empirical formula can be found here:brainly.com/question/14044066
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Answer:
The answer to 12 is Indium... you should be able to figure out the rest from there with help from the internet since i've given you the element
Explanation:
I would usually do it but I got a ton of hw
