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asambeis [7]
4 years ago
12

Which statement correctly describes part of the atomic model?

Chemistry
2 answers:
Ganezh [65]4 years ago
5 0
The answer is D.  A is incorrect because neutrons are an integral part of atoms. B is incorrect because electrons can't be in the nucleus. C is false because protons are only outside the nucleus in antimatter.
denis23 [38]4 years ago
4 0

Answer: D

Explanation:

In an atomic model of an atom, the nucleus consists of protons and neutrons while the electrons revolves round its orbitals outside the nucleus. The protons are positively charged while the electrons are negatively charged so as to counter electric charges and make the atom electrically neutral.

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Ions are atoms or groups of atoms that have either gained or lost electrons
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A sample of metal has a mass of 23.04 g, and a volume of 5.31 ml. what is the density of this metal?
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Read 2 more answers
You are given a stock solution of 500.0 mL of 1.00M magnesium chloride solution. Calculate the volume of the stock solution you
alexgriva [62]

Answer:

50\; \rm mL of the stock solution would be required.

Explanation:

Assume that a solution of volume V contains a solute with a concentration of c. The quantity n of that solute in this solution would be:

n = c \cdot V.

For the solution that needs to be prepared, c = 0.20\; \rm M = 0.20\; \rm mol \cdot L^{-1}. The volume of this solution is V = 250.0\; \rm mL. Calculate the quantity of the solute (magnesium chloride) in the required solution:

\begin{aligned}n &= c \cdot V \\ &= 0.20\; \rm mol \cdot L^{-1} \times 250.0\; \rm mL \\ &= 0.20\; \rm mol \cdot L^{-1} \times 0.2500\; \rm L \\ &= 0.050\; \rm mol\end{aligned}.

Rearrange the equation n = c \cdot V to find an expression of volume V, given the concentration c and quantity n of the solute:

\displaystyle V= \frac{n}{c}.

Concentration of the solute in the stock solution: c(\text{stock}) = 1.00\; \rm M = 1.00\; \rm mol \cdot L^{-1}.

Quantity of the solute required: n = 0.050\; \rm mol.

Calculate the volume of the stock solution that would contain the required n = 0.050\; \rm mol of the magnesium chloride solute:

\begin{aligned}& V(\text{stock}) \\ &= \frac{n}{c(\text{stock})} \\ &= \frac{0.050\; \rm mol}{1.00\; \rm mol \cdot L^{-1}} \\ &= 0.050\; \rm L \\ &= 50\; \rm mL\end{aligned}.

3 0
3 years ago
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