Answer:
15.9994 amu
Explanation:
By definition 1 mole of any substance is the mass that contains 1 Avogadro's Number of particle. (=> 6.02 x 10²³ particles/mole).
1 mole Oxy => 15.9994 amu => contains 6.02 x 10²³ particles Oxy /mole
1 mole Sulfur => 32.064 amu => contains 6.02 x 10²³ particles Sulfur /mole
1 mole H₂O => 18 amu => contains 6.02 x 10²³ molecules of water / mole.
Answer:
1.3x10⁻⁸ mol/L
Explanation:
<em>0.0013μmol, Calculate concentration in mol/L</em>
<em />
To obtain concentration in mol/L we need to convert the μmoles to moles and mL to liters:
<em>Moles silver(II) oxide:</em>
0.0013μmol × (1mol / 1x10⁶μmol) = 1.3x10⁻⁹ moles
<em>Liters solution:</em>
100mL * (1L / 1000mL) = 0.1L
That means concentration in mol/L is:
1.3x10⁻⁹ moles / 0.1L =
<h3>1.3x10⁻⁸ mol/L</h3>
Answer:
1.32 moles.
Explanation:
From the question given above, the following data were obtained:
Density of Al = 2.70 g/cm³
Volume of Al = 13.2 cm³
Number of mole of Al =.?
Next, we shall determine the mass of Al.
This can be obtained as follow:
Density of Al = 2.70 g/cm³
Volume of Al = 13.2 cm³
Mass of Al =?
Density = mass / volume
2.7 = mass of Al / 13.2
Cross multiply
Mass of Al = 2.7 × 13.2
Mass of Al = 35.64 g
Finally, we shall determine the number of mole of Al. This can be obtained as follow:
Mass of Al = 35.64 g
Molar mass of Al = 27 g/mol
Number of mole of Al =?
Mole = mass / molar mass
Number of mole of Al = 35.64 / 27
Number of mole of Al = 1.32 moles
Thus, 1.32 moles of aluminum are present in the block of the metal.
Answer:
O Continental-continental convergent boundary
Explanation:
Hope it helps.
Answer:
The correct answer is option d/ "all above".
Explanation:
Exponential notation is a way of expressing mathematical equations by simplifying numbers that could be very small or very large. The number included within the exponential notation (the exponent) describe how many times the number included in the base is multiplied. If the exponent is an integer the number is very large, while if the exponent is a ratio the number is very small. This avoids the tedious work of writing the complete number that results from the exponential multiplication.
