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DedPeter [7]
3 years ago
6

When two people push a stationary box to the right,____.

Physics
2 answers:
Lena [83]3 years ago
4 0
When two forces act in the same direction, they add together. When forces act in opposite directions, they are combined by subtracting the smaller force from the larger force.
nlexa [21]3 years ago
3 0
Las cosas que se pueden decir en un mundo que no es una de las más difíciles que la mujer es el único que
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Suppose a soup can is made from a sheet of steel19 which is .13 mm thick. If the can is 11 cm high and 6 cm in diameter, use dif
Flura [38]

Answer:

The can mass is 0,00359 kg or 3,59 g

Explanation:

1. Relevant Data:

Steel thickness= 0.13 mm or 0.013 mm

h=11 cm

d=6 cm

ρ=800 kg/m^3

2. Calculate mass from densisty equation:

\rho=\frac{m}{v}, then m=\rho .v

We need to estimate the volume of the can to calculate the mass.

3. Estimate volume using differentials:

Cylinder volume equation is:

V=\frac{1}{4}\pi  d^{2}h

Considering that the can is an object with a hole inside, then we need to estimate the real volume of the sheet of steel.

Using differentials we have:

dV=\frac{1}{2}\pi  Dh (dD)

Then, we could say that dD=0.013 cm

Replacing the values of d, h and dD, we obtain:

dV=\frac{1}{6}\pi  (6 cm)(11 cm)(0,013 cm)

dV=0,4492 cm^3

4. Calculate the mass

Convert volume unit into m^3

0,4492 cm^3x\frac{1 m^3}{1x10^6 cm^3} =0,4492 x 10^-6 m^3

Calculate mass

m=\rho .v

m=8000 \frac{kg}{m^3}.0,4492 x10^-6 m^3

m=0,00359 kg =3,59 g

5 0
4 years ago
An athlete runs at a constant velocity of 5.2 m/s. What is the velocity of the athlete relative to the ground?
dimulka [17.4K]

The relative velocity of the athlete relative to the ground is 5.2 m/s

The given parameters;

constant velocity of the athlete, V = 5.2 m/s

let the velocity of the ground = Vg = 0

The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.

The athlete is the moving object in this question while the ground is stationary.

The relative velocity of the athlete relative to the ground is calculated as follows;

V/V_g = V - V_g  = 5.2 - 0 = 5.2  \ m/s

Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s

Learn more here: brainly.com/question/24430414

5 0
3 years ago
When developing an experimental design which action could a scientist take to improve the quality of the results
Anni [7]

Answer:

However, scientific findings in biomedical research are not always reproducible. ... that are promoting best practices and helping researchers perform the highest-quality science. ... in life science research and actions that can be taken to improve it. ... when designing experiments, take responsibility for depicting their results ...

Explanation:

4 0
3 years ago
Suppose that the design parameters of the satellite's control system require that the angular velocity of the satellite not exce
Stells [14]

Answer:

v=0.04m/s

Explanation:

To solve this problem we have to take into account the expression

\omega=\frac{v}{r}

where v and r are the magnitudes of the velocity and position vectors.

By calculating the magnitude of r and replacing w=0.02rad/s in the formula we have that

|r|=\sqrt{(-1.18m)^2+(-0.9m)^2}=2.01m\\\\v=\omega r=(0.02\frac{rad}{s})(2.01m)=0.04\frac{m}{s}

the maximum relative velocity is 0.04m/s

hope this helps!!

6 0
3 years ago
Read 2 more answers
How are the variables speed and velocity different? how are they similar
victus00 [196]

Answer:

Speed, being a scalar quantity, is the rate at which an object covers distance. The average speed is the distance (a scalar quantity) per time ratio. ... Velocity is the rate at which the position changes. The average velocity is the displacement or position change (a vector quantity) per time ratio.

Explanation:

3 0
3 years ago
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