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3 years ago

The place theory of hearing is better than frequency theory at explaining pitch perception for __________ sounds

Physics

2 answers:

Licemer1 [7]3 years ago

6 0

Answer choices are:

A. low frequency

B. low and high frequency

C. mid-range

D. high frequency

____________________________________________________________

Correct answer choice is:

A. Low frequency .

____________________________________________________________

Explanation:

Place theory is a theory of hearing which declares that our judgment of sound depends on where each element frequency generates oscillations along the basilar layer. According to the frequency theory, the pulse rate of the nerve vibrations of the hearing nerve communicates to the rate of a pitch, which enables us to identify its pitch. The complete basilar layer is stimulated by sound waves at various frequencies.

atroni [7]3 years ago

5 0

The answer is : Low frequency sounds

place theory is a theory of hearing which states that our perception of sound depends on where each component frequency produces vibrations along basilar membrane, which is very sensitive to low frequency sound

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Akimi4 [234]

Answer:

Approximately $122.625\; {\rm m}$ (assuming that $g = 9.81\; {\rm m\cdot s^{-2}}$ , the ball was launched from ground level, and that the drag on the ball is negligible.)

Explanation:

Let $v_{0}$ denote the velocity at which the ball was thrown upward.

If the drag (air friction) on the ball is negligible, the ball would land with a velocity of exactly $(-v_{0})$ . The velocity of the ball would be changed from $v$ to $(-v_{0})\!$ (such that $\Delta v = (-v_{0}) - v_{0} = (-2\, v_{0})$ ) within $t = 10\; {\rm s}$ .

Also because the drag on the ball is negligible, the acceleration of the ball would be $a = -g = -9.81\; {\rm m\cdot s^{-2}}$ . Thus:

$\Delta v = a\, t = 10\; {\rm s} \times (-9.81\; {\rm m\cdot s^{-2}}) = -98.1\; {\rm m\cdot s^{-1}}$ .

Since $\Delta v = (-2\, v_{0})$ :

$-2\, v_{0} = \Delta v = -98.1\; {\rm m\cdot s^{-1}$ .

$\begin{aligned}v_{0} &= \frac{-98.1\; {\rm m\cdot s^{-1}}}{-2}= 49.05\; {\rm m \cdot s^{-1}}\end{aligned}$ .

The ball reaches maximum height when its velocity is $v_{1} = 0\; {\rm m\cdot s^{-1}}$ . Apply the SUVAT equation $x = ({v_{1}}^{2} - {v_{0}}^{2}) / (2\, a)$ to find the displacement $x$ between the original position (ground level, where $v_{0} = 49.05\; {\rm m\cdot s^{-1}}$ ) and the max-height position of the ball (where $v_{1} = 0\; {\rm m\cdot s^{-1}}$ .)

$\begin{aligned}x &= \frac{(0\; {\rm m\cdot s^{-1}})^{2} - (49.05\; {\rm m\cdot s^{-1}})^{2}}{2 \times (-9.81\; {\rm m\cdot s^{-2}})} \\ &\approx 122.625\; {\rm m\cdot s^{-1}}\end{aligned}$ .

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lilavasa [31]

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But since the force has been inclined at an angle θ above the horizontal, the horizontal component of force is neccesary to produce the required motion to make the child do work on the wagon.

Hence

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lara31 [8.8K]

Answer:

Explanation:

Hello friend!!!

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