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3 years ago

What do conduction, radiation, and convection work together to do?

1 answer:

6 0

Well, conduction is the passing of heat by touch. Convection is the passing along of heat by movement (e.g. hot air rising from a radiator to heat the rest of the room), and radiation is the heating of something through electromagnetic rays without any contact. For example, the earth absorbs the heat radiated from the son (radiation). The air that touches the earth gets warmed up (conduction), and rises, and as it rises, it passes its heat along to more air around it (convection).

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The half-life for the radioactive decay of U-238 is 4.5 billion years and is independent of initial concentration. How long will

Setler [38]

Answer:

Explanation:

Given

half life $(t_{\frac{1}{2})=4.5$ billion year

10 % to decay i.e. 90 % remaining

And $\ln (\frac{C}{C_0})=-kt$

where k= constant

t=time

and $k=\frac{\ln (2)}{t_{\frac{1}{2}}}=\frac{\ln (2)}{4.5}$

so $\frac{C}{C_0}=0.9$

$\ln (0.9)=-\frac{\ln (2)}{4.5}\times t$

t=0.684 billion year

(b) $C_0=1.5\times 10^{18}$

t=13.8 billion year

$\ln (\frac{C}{C_0})=-0.15403\times 13.8$

$\ln (\frac{C}{C_0})=-2.125$

$C=C_0e^{-2.125}$

$C=1.5\times 10^{18}\times 0.1194=0.179\times 10^{18}$ atoms

6 0

3 years ago

Classical mechanics is an extremely well tested model. Hundreds of years worth of experiments, as well as most feats of engineer

djyliett [7]

Answer:

The Answer is 0.019998c

Explanation:

Please see the attached Picture for the answer.

7 0

2 years ago

A potter's wheel rotating at 355 rev/min is switched off and rotates through 76.0 revolutions prior to coming to rest. What is t

Aliun [14]

Answer:

-1.44707 rad/s²

Explanation:

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity = 355 rpm

$\alpha$ = Angular acceleration

$\theta$ = Angle of rotation = 76 rps

Converting rpm to rad/s

$1\ rpm=\frac{2\pi}{60}\ rad/s$

Converting rps to rad/s

$1\ rps=2\pi \ rad/s$

Equation of rotational motion

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{0^2-355\times \frac{2\pi}{60}^2}{2\times 2\pi \times 76}\\\Rightarrow \alpha=-1.44707\ rad/s^2$

The constant angular acceleration of the potter's wheel during this interval is -1.44707 rad/s²

4 0

2 years ago

From rest a skier skies decencing on the 30 degree slope .the coefficient of kinectic friction is 0.10

Degger [83]

Answer:) Calculate the acceleration of a skier heading down a. 10.0º slope, assuming the coefficient of friction for waxed.

Explanation:

I believe this is right I'm not sure so if I'm rong let me know please.

8 0

2 years ago

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Alja [10]

Answer:

Explanation:

5 0

2 years ago