I believe the answer is D.
Answer:
Iron (lll) oxide reacts with carbon monoxide according to the equation: Fe203(s) + 3 CO(g)-2Fe(s) + 3 CO2(g) A reaction mixture initially contains 22.55 g Fe203 and 14.78 g CO.
Explanation:
I hope this helps (:
Answer:
D) 6
Explanation:
The balanced equation would be:
6Li + N2 -> 2Li3N
Sorry it’s a bit blurry, you should be able to make it out
The atomic mass of the metal.(M) = 51 g/mol
<h3>Further explanation</h3>
Given
32% of oxygen
Required
the atomic mass of the metal.
Solution
An oxide of trivalent metal : M₂O₃(Ar O = 16 g/mol)
The molar mass of metal oxide = 2M+16.3=2M+48
32% of oxygen, then :
32% x 2M+48 = 48
0.32(2M+48)=48
0.64M+15.36=48
0.64M=32.64
M=51