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Elodia [21]
2 years ago
6

What is the average salinity of ocean water?

Chemistry
2 answers:
sergiy2304 [10]2 years ago
7 0
35 parts per thousandOn average, seawater in the world's oceans has a salinity of approximately 3.5%, or 35 parts per thousand. (For every 1 litre (1000 mL) of seawater there are 35 grams of salts.)

Therefore, your answer is 34.5 g/mL
Ratling [72]2 years ago
6 0

Answer:

<h2>34.5 g/mL</h2>

Explanation:

<h3>Actually sea water salinity is 35 grams per litre (average).</h3><h3>Which means: \frac{35g}{1L}</h3>
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it would appear to be more concentrated than it should be because more base was added that should have been

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A solution of a specific vitamin has λmax = 273 nm and a concentration of 8.33 × 10-7 m. the absorbance of the solution at 273 n
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Just pay attention in school big bones, stop asking people because if they mislead you that will not be good for you're college education.
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2 years ago
Iodine-131 half life 8.040 how long will it take for a 40 gram sample of iodine-131 to decay to 0.75 grams
otez555 [7]

Answer:

See explanation below

Explanation:

To get this, we need to apply the general expression for half life decay:

N = N₀e(-λt)    (1)

Where:

N and N₀ would be the final and innitial quantities, in this case, masses.

t: time required to decay

λ: factor related to half life

From the above expression we need λ and t. To get λ we use the following expression:

λ = t₁₂/ln2   (2)

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λ = 8.04 / ln2 = 11.6

Now, we can replace in (1) and then, solve for t:

0.75 = 40 exp(-11.6t)

0.75 / 40 = exp(-11.6t)

ln(0.01875) = -11.6t

-3.9766 = -11.6t

t = -3.9766 / -11.6

<h2>t = 0.34 days</h2><h2></h2>
3 0
3 years ago
CAN ANYONE PLEASE HELP MY BOOKS ARENT HELPING!!!! THIS IS FOR FIRE TECH
Mazyrski [523]

Answer:

The answer to the question is;

The occupant load of the store having a floor area of 100,000 ft² is 3,317.86 persons.

Explanation:

Based on NFPA guidelines  we have for sales on street floor, the allowable occupant load factor per person is 30 ft²

That is where  the floor area is 100,000 square feet we have the number of allowable occupant given by

(100,000 ft²)/(30 ft²/Person) = \frac{10000}{3} Persons or 3,333 persons

That is the  occupant load of the store if the floor area is 100,000 square feet = 3,333 persons

Based on m² we have  9,290 m² will require 2.8 m²/person

which gives;

(9,290 m²)/(2.8 m²/person) = \frac{9290}{2.8} Persons = 23225/7 or 3,317.86 persons

Therefore applying safety, we go with the lesser number and we have

The occupant load of the store having a floor area of 9,290 m² = 3,317.86 persons.

5 0
3 years ago
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