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Elodia [21]
3 years ago
6

What is the average salinity of ocean water?

Chemistry
2 answers:
sergiy2304 [10]3 years ago
7 0
35 parts per thousandOn average, seawater in the world's oceans has a salinity of approximately 3.5%, or 35 parts per thousand. (For every 1 litre (1000 mL) of seawater there are 35 grams of salts.)

Therefore, your answer is 34.5 g/mL
Ratling [72]3 years ago
6 0

Answer:

<h2>34.5 g/mL</h2>

Explanation:

<h3>Actually sea water salinity is 35 grams per litre (average).</h3><h3>Which means: \frac{35g}{1L}</h3>
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Where are fusion reactions found
Paha777 [63]

Answer:

In a nuclear fusion reaction, the nuclei of two atoms combine to create a new atom. Most commonly, in the core of a star, two hydrogen atoms fuse to become a helium atom. Although nuclear fusion reactions require a lot of energy to get started, once they are going they produce enormous amounts of energy.

Explanation:

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In a diagnostic test for leukemia, a person receives 4.1 mL of a solution containing selenium-75. If the activity of the seleniu
Tcecarenko [31]

To solve this problem, we can simply calculate for the dose by multiplying the volume of solution containing Selenium 75 and the activity of the Selenium 75. That is:

dose = 4.1 mL * (45 μCi/mL)

dose = 184.5 μCi

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. Where exactly in our solar system is this water found?
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Answer: Earth, though the dwarf planet Pluto does have ice on it.

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3 years ago
The number of grams of H2 in 1470 mL of H2 gas. ​
Lorico [155]

Answer:

0.1313 g.

Explanation:

  • It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
  • Suppose that hydrogen behaves ideally and at STP conditions.

<u><em>Using cross multiplication:</em></u>

1.0 mol of hydrogen occupies → 22.4 L.

??? mol of hydrogen occupies → 1.47 L.

∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.

  • Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:

<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>

5 0
3 years ago
what is the mole fraction of neon in a mixture that contains 0.628 g of helium, 11.491 g of neon, and 7.613 g of argon?​
VMariaS [17]

Answer:

0.2

Explanation:

Given parameters:

Mass of helium = 0.628g

Mass of neon = 11.491g

Mass of argon = 7.613g

Unknown:

Mole fraction of neon = ?

Solution:

The mole fraction of an element is the number of moles of that element to the total number of moles in the gas mixture.

We need to calculate the number of moles of each element first;

 Number of moles  = \frac{mass}{molar mass}

Molar mass of Helium = 4g/mol

Molar mass of Neon = 20g/mol

Molar mass of Argon = 40g/mol

Number of moles of He = \frac{0.628}{4} = 0.16moles

Number of moles of Ne = \frac{11.491}{20} = 0.58moles

Number of moles of Ar = \frac{7.613}{40} = 0.19moles

Total number of moles = 0.16moles + 0.58moles + 0.19moles = 0.93moles

Mole fraction Neon = \frac{0.19}{0.93}  = 0.2

4 0
3 years ago
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