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Galina-37 [17]
1 year ago
10

Question is in picture below

Chemistry
1 answer:
liq [111]1 year ago
8 0

The dissociation of cadmium chloride is as follows: CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

<h3>What is dissociation?</h3>

Dissociation is the process by which a compound body breaks up into simpler constituents; said particularly of the action of heat on gaseous or volatile substances.

It is a chemical reaction in which a compound breaks apart into two or more components. The general formula for a dissociation reaction follows the form:

AB → A + B

According to this question, cadmium chloride undergoes dissociation into cadmium and chlorine ions as follows:

CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

Learn more about dissociation at: brainly.com/question/28952043

#SPJ1

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Sodium hydride reacts with excess water to produce aqueous sodium hydroxide and hydrogen gas:NaH (s) H2O (l) → NaOH (aq) H2 (g)A
Anuta_ua [19.1K]

NaH(s)+ H2O (l)=>NaOH(aq)+H2(g)

You want to calculate the mass of NaH, I assume.  Otherwise, the question isn't clear.  It simply says calculate the mass(??)

 

So, calculate the moles of H2 gas that satisfy the conditions of 982 ml at 28ºC and 765 torr.  But you must subtract the vapor pressure of water at 28º to get the actual pressure of the H2 gas.  So, the actual conditions are 982 ml (0.982 L) and 301 K and 765-28 = 737 torr.

PV = nRT

n = PV/RT = (737 torr)(0.982 L)/(62.4 L-torr/Kmol)(301 K)

n = 0.0385 moles H2

 

moles NaH needed = 0.0385 moles H2 x 1 mole NaH/mole H2 = 0.0385 moles NaH required

mass of NaH needed = 0.0385 moles x 24 g/mole = 0.925 g NaH

Brainliest Please :)

7 0
3 years ago
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Reaccionan 54gr de Nitrato de plata al 39 % de pureza, con 72gr de ácido clorhídrico al 83% de pureza, en un proceso donde se ob
netineya [11]

Answer:Reaccionan 54gr de Nitrato de plata al 39 % de pureza, con 72gr de ácido clorhídrico al 83% de pureza, en un proceso donde se obtienen 93 gr de cloruro de - 154… ... 93 gr de cloruro de plata. El otro producto es el ácido nítrico: Calcular el porcentaje de rendimiento de la reacción y balancearlo.

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3 years ago
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ICE Princess25 [194]

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The person who just wanted points is annoying

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8 0
3 years ago
A buffer solution is composed of 1.00 mol of acid and 2.25 mol of the conjugate base. If the p K a of the acid is 4.90 , what is
Gemiola [76]

<u>Answer:</u> The pH of the buffer is 5.25

<u>Explanation:</u>

Let the volume of buffer solution be V

We know that:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution}}

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{conjugate base}]}{[acid]})

We are given:

pK_a = negative logarithm of acid dissociation constant of weak acid = 4.90

[\text{conjugate base}]=\frac{2.25}{V}

[acid]=\frac{1.00}{V}

pH = ?

Putting values in above equation, we get:

pH=4.90+\log(\frac{2.25/V}{1.00/V})\\\\pH=5.25

Hence, the pH of the buffer is 5.25

4 0
3 years ago
Electrons in conductors, like copper wire, are free to roam throughout the metal in the presence of the ions that have released
Scrat [10]

Answer:

  • <u><em>No, I would not consider a metal to be a plasma because plasma is just another state of matter, and the copper wire is in solid state.</em></u>

Explanation:

Metal is not a state of matter. Metals can be solid or liquid (molten) depending on their melting point and the temperature at which they are.

Plasma is a state of matter, similar to gas, but it is reached only at very high temperatures like in the Sun. The particles in plasma state are not neutral atoms or molecules but negatively charged  ions and electrons.

The copper wire is yet a solid, thus it cannot be considered a plasma.

Metals can be in plasma state only if the temperature is too high, like the temperatures in the stars. In fact, the metals in the Sun and other hotter stars are in plasma state.

5 0
3 years ago
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