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Shkiper50 [21]
3 years ago
15

If a sample has 25% parent and 75% daughter, how many halflifes have gone by?

Chemistry
1 answer:
Anit [1.1K]3 years ago
6 0

Answer:

Two half lives.

Explanation:

It is known that the decay of isotopes and radioactive material obeys first order kinetics.

Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

That means for a sample 100% to decay to 50 % it will take one half-life, and to decay the remaining 50% to 25% it will take another half-life.

So, for a sample has 25% parent and 75% daughter it will have two half-lives.

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Serhud [2]

Answer:

graduated cylinder

Explanation:

It shows exact volume very precisely.

8 0
3 years ago
Can someone help me thank you. I have to look at each picture and determine if the circuits shown are series circuits or paralle
rodikova [14]

Answer:

I believe it may be-

1. Series

2. Parallel

3. Parallel

4. Series

Explanation:

In a series circuit, electricity only has one path to follow while a parallel circuit has more than one path to follow.

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3 years ago
1. How much energy (in KJ) is required to convert 50.0g of ice at – 30 ˚C to<br> steam at130˚C.
Vitek1552 [10]

Answer:

How much heat energy required to convert following?

How much heat energy, in kilojoules, is required to convert 47.0 g of ice at -18.0 C to water at 25.0 C ?

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This is how I did it and the answer is wrong...Please check and correct me

Q = m * Cice * Change in Temp

Q = (47.0 g)(2.09 J/g*c)(43) = 4222.6 J * 0.001 kj / j = 4.22 kj

4 0
3 years ago
Which of the following is true of solids?
Over [174]
<span>Answer: B. Ionic solids have higher melting points than molecular solids.
</span>
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5 0
3 years ago
32.33 mL of 1.031 M potassium hydroxide were required to reach the endpoint of a titration of 50.00 mL of nitric acid. What was
tester [92]

The molar concentration of the nitric acid solution was 0.6666 mol/L.

<em>Balanced equation</em>: KOH + HNO_3 → KNO_3 + H_2O

<em>Moles of KOH</em>: 32.33 mL KOH × (1.031 mmol KOH /1 mL KOH)

= 33.33 mmol KOH

<em>Moles of HNO_3</em>: 33.33 mmol KOH× (1 mmol HNO_3/1 mmol KOH)

= 33.33 mmol HNO_3

<em>Concentration of KOH</em>: <em>c </em>= "moles"/"litres" = 33.33 mmol/50.00 mL

= 0.6666 mol/L

4 0
3 years ago
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