Impulse is the change in momentum.
All we need is the momentum before and after.
Momentum = (mass) x (speed)
Before: = (80 kg) x (4.7 m/s) = 376 kg-m/s
After: = (80 kg) x (3.4 m/s) = 272 kg-m/s
Change in momentum = (376 - 272) = <span>104 kg-m/s
</span>Notice that when you work with impulse, you're USUALLY calculating
(force) x (time).
The force is in Newtons, and the time is in seconds,
so the impulse is usually in units of
Newton-seconds .
So how can I say that impulse and change of momentum are
the same thing ? Am I trying to pull a fast one on you ?
Remember that 1 Newton is 1 kg-m/s²
So (force) x (time)
= (Newton) x (second)
= (kg-m/s²) x (second) = kg-m/s .
and Momentum = (mass) x (speed) = (kg) x (m/s)
The units of impulse are the same as the units of momentum !
So when you give an object some impulse, you give it exactly
that much momentum.
Answer:
it represents group 2 and also it represents the group 3 stars
Explanation:
because i just took it and got it correct.
Galaxies are comprised of groups of stars circling a common gravitational point (which is theorized in the Milky Ways case to be a black hole). The answer is True.
Answer:
Sa
Explanation:
Spiral Galaxies -
It is a disk shaped galaxies which have spiral structure , is refereed to as spiral galaxies .
According to Hubble , these galaxies are classified as Sa , Sb , Sc .
Where ,
Sa - have the structure , which is bulged from the central portion , along with a tightly wrapped spiral structure .
Sb - have a lesser bulge and the spiral is looser .
Sc - It has very weak bulge with the open spiral structure .
Hence , from the question ,
The given information is about the Sa .
Your acceleration before you throw the ball is zero. After the throw, you use the equation
<span>F = m * a </span>
<span>To solve for acceleration </span>
<span>a = F/m </span>
<span>a = (10 N) / (50 kg) </span>
<span>a = 0.2 m/s^2</span>
